Answer:
0.57142
Step-by-step explanation:
A normal random variable with mean and standard deviation both equal to 10 degrees Celsius. What is the probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit?
We are told that the Mean and Standard deviation = 10°C
We convert to Fahrenheit
(10°C × 9/5) + 32 = 50°F
Hence, we solve using z score formula
z = (x-μ)/σ, where
x is the raw score = 59 °F
μ is the population mean = 50 °F
σ is the population standard deviation = 50 °F
z = 59 - 50/50
z = 0.18
Probability value from Z-Table:
P(x ≤59) = 0.57142
The probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit
is 0.57142
Answer:
b = 4,
m = 4/3,
y = 4x/3 + 4
Step-by-step explanation:
We can see the line intercepts the x-axis in (-3,0) and the y-axis in (0,4). So, using the fact that the line equation in the slope-intercept form is:

We can substitute the points we know:
→ (0,4):

→ (-3,0):

So, the line equation in form requested is:

Answer:
10 map squares.
Step-by-step explanation:
We have been given a histogram, which represents the plant species spotted in the animal reserve.
The x-axis represents the number of plant species and y axis represents the number of map squares.
We can see that 0 to 9 species are spotted in 1 map square.
10 to 19 and 20 to 29 plant species are spotted in 2 map squares.
To find the number of map squares that spot more than 29 plant species, we will count number of map squares that spot 30 to 49 plant species as 30 to 49 numbers are more than 29.
We can see from our histogram that 4 map squares spot 30 to 39 plant species and 6 map squares spot 40 to 49 plant species.


Therefore, 10 map squares spot more than 29 plant species.
The answer is 9/10 because I did the test and that was the answer
Step-by-step explanation:
Since, K is the midpoint of JL.
