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sergij07 [2.7K]
3 years ago
15

The Highest Common Factor of three numbers is 6 and the Lowest Common Multiple is 24 What are the three numbers?​(PLEASE HELP)​

Mathematics
1 answer:
vazorg [7]3 years ago
6 0

Answer:

GCF of 3 and 6 is 3.

LCM of 3 and 6 is 6.

Step-by-step explanation:

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) An instructor gives his class a set of 18 problems with the information that the next quiz will consist of a random selection
RSB [31]

Answer:

The probability the he or she will answer correctly is 1.5%

Step-by-step explanation:

In all, there are 18 problems. In this question, the order of which the problems are sorted for the quiz makes no difference. For example, if the question A of the quiz is P1 and question B P2, and question A P2 and question B P1, it is the same thing.

There are 18 problems and 9 are going to be selected. So, there is going to be a combination of 9 elements from a set of 18 elements.

A combination of n elements from a set of m objects has the following formula:

C_{(m,n)} = \frac{m!}{n!(m-n)!}

In this question, m = 18, n = 9. So the total number of possibilities is:

T_{p} = C_{(18,9)} = \frac{18!}{9!(18-9)!} = 48620

Now we have to calculate the number of desired outcomes. This number is a combination of 9 elements from a set of 13 elements(13 is the number of problems that the student has figured out how to do).

Now, m = 13, n = 9. The number of desired possibilities is:

D_{p} = C_{(13,9)} = \frac{13!}{9!(13-9)!} = 715

The probability is the number of desired possibilities divided by the number of total possibilities. So

P = \frac{715}{48620} = 0.015 = 1.5%

The probability the he or she will answer correctly is 1.5%

3 0
3 years ago
What are the coordinates of the midpoint of AB IF A (6,4) and B (-8,8)
marissa [1.9K]

Answer:

-I haven't done this, but I have copied and pasted from another question and answer from the user syed514:

Graphing is one way to do the problem.But sometimes, graphing it is hard to do.So here’s an algebraic method.

If M(m1, m2) is the midpoint of two points A(x1, y1) and B(x2, y2),then m1 = (x1 + x2)/2 and m2 = (y1 + y2)/2.In other words, the x-coordinate of the midpointis the average of the x-coordinates of the two points,and the y-coordinate of the midpointis the average of the y-coordinates of the two points.

Let B have coordinates (x2, y2) in our problem.Then we have that 6 = (2 + x2)/2 and 8 = (3 + y2)/2.

Solving for the coordinates gives x2 = 10, y2 = 13

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3 years ago
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2 * (2a + b) + 8 = 4a + 2b + 8
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A.  =
B.  =
C.  ≠      4* (a + b + 2) = 4a + 4b + 8
D. =
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