Y + 2 = -3/4(x+1) Standard form.
1 answer:
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Answer:
The p-value of the test is of 0.2776 > 0.01, which means that the we accept the null hypothesis, that is, the manager's claim that this is only a sample fluctuation and production is not really out of control.
Step-by-step explanation:
A manufacturer considers his production process to be out of control when defects exceed 3%.
At the null hypothesis, we test if the production process is in control, that is, the defective proportion is of 3% or less. So
At the alternate hypothesis, we test if the production process is out of control, that is, the defective proportion exceeds 3%. So
The test statistic is:
In which X is the sample mean, is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
0.03 is tested at the null hypothesis
This means that
In a random sample of 100 items, the defect rate is 4%.
This means that
Value of the test statistic:
P-value of the test
The p-value of the test is the probability of finding a sample proportion above 0.04, which is 1 subtracted by the p-value of z = 0.59.
Looking at the z-table, z = 0.59 has a p-value of 0.7224
1 - 0.7224 = 0.2776
The p-value of the test is of 0.2776 > 0.01, which means that the we accept the null hypothesis, that is, the manager's claim that this is only a sample fluctuation and production is not really out of control.
Answer:
x = 1
Step-by-step explanation:
There are a couple of ways to solve this. One is to graph the left side of the equation, graph the right side of the equation, and look for the point where those graphs intersect. It is at x = 1. The first attached graph shows this solution.
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Another method for solving such an equation is to subtract one side from the other and look for the value of x that makes the resulting expression zero.
(-2x +3) -(-3(-x) -2) = 0
A graphing calculator doesn't need to have this simplified. If it is simplified, it becomes ...
-5x +5 = 0
So, the graphed line is y = -5x+5. Its x-intercept is x=1, the solution of the original equation. The graph of this is shown in the second attachment.
