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Arlecino [84]
3 years ago
15

Is one over one-third a unit rate

Mathematics
2 answers:
ANTONII [103]3 years ago
7 0
No because a unit rate is a rate where the second quantity is one unit such as 34$ per pound, 25 miles per hour
miss Akunina [59]3 years ago
5 0

Answer: NO it is not a unit rate

Step-by-step explanation:

No, a unit rate is the amount for 1 item or unit. and 1/ 1/3, 1/3 is on the bottom

1/3≠1 so no

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The answer of the problem
k0ka [10]

Answer:

x=16 and x=-3

Step-by-step explanation:

A <em>second-degree equation</em> or <em>quadratic equation of a variable</em> is an equation that it has the general expression:

ax^{2} +bx+c=0 with a\neq 0

Where x is the variable, and a, b and c constants; a is the quadratic coefficient (other than 0), b the linear coefficient and c is the independent term. This polynomial can be interpreted by means of the graph of a quadratic function, that is, by a parabola. This graphical representation is useful, because the abscissas of the intersections or point of tangency of this graph, in the case of existing, with the X axis are the real roots of the equation. If the parabola does not cut the X axis the roots are complex numbers, they correspond to a negative discriminant.

Second degree equation solutions

For a quadratic equation with real or complex coefficients there are always two solutions, not necessarily different, called roots, which can be real or complex (if the coefficients are real and there are two non-real solutions, then they must be complex conjugates). General formula for obtaining roots:

x=\frac{-b±\sqrt{b^{2} -4ac} }{2a}

The discriminant serves to analyze the nature of the roots that can be real or complex.

Δ=b^{2} -4ac

Solving the problem of the answer.

x^{2} -13x-48=0 with a = 1, b = -13, and c = -48

Substituting the values in the general formula for a quadratic equation.

x=\frac{-(-13)±\sqrt{(-13)^{2} -4(1)(-48)} }{2(1)}

x=\frac{13±\sqrt{169+192} }{2}

x=\frac{13±\sqrt{361} }{2}

Then, we obtain the roots:

x=\frac{13+\sqrt{361} }{2} and x=\frac{13-\sqrt{361} }{2}

Solving the roots:

x=\frac{13+\sqrt{361} }{2}\\x=\frac{13+19}{2}\\x=\frac{32}{2}\\x=16

x=\frac{13-\sqrt{361} }{2}\\x=\frac{13-19}{2}\\x=\frac{-6}{2}\\x=-3

4 0
3 years ago
Jessica thinks of a number
kow [346]

Answer:

4

Step-by-step explanation:

if you multiply 4 by 3, you will get 12, and if you subtract 7, you get 5. I hope this helps ;)

6 0
3 years ago
Read 2 more answers
Please help me!!! It's due in a hour and I have a lot on my plate!!
Sergio039 [100]

Answer:

1. +35

2. -270 ft.

3. -$12

4. +19°

5. -15 ft

6. +$25

hope this helps :)

5 0
3 years ago
Read 2 more answers
A group of friends went to the movies together. The ticket price was $9.00 per
zhuklara [117]

Answer:

4 people

Step-by-step explanation:

9-2= $7

28/7 = 4

3 0
3 years ago
Is y=1/15x proportional or not
EastWind [94]

Answer:

Yes

Step-by-step explanation:

They are inversely proportional

Means if we increase y then the value of x will decrease and vice versa.

4 0
3 years ago
Read 2 more answers
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