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kirill [66]
3 years ago
13

HELPPPP PLEASE!!!!!!

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
8 0

Answer:

x = 7

Step-by-step explanation:

7x - 12 = 9x - 26

7x - 12 = 9x - 26

+12 +12

7x = 9x - 14

7x = 9x - 14

-9x -9x

-2x = -14

-2x = -14

___. ___

-2 -2

x = 7

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A portion of the Quadratic Formula proof is shown. Fill in the missing reason
Dahasolnce [82]

Answer:

The first one

Step-by-step explanation:

I believe it is the first option, as you can see that, on the right hand side, 4a was multiplied to the first term to make a common denominator. I'm sorry if it is wrong, and I hope this helped.

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4 years ago
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Find the values of a and b such that
Varvara68 [4.7K]

Answer:

a = 1.5

b = 1.75

Step-by-step explanation:

First, we need to solve (x+a)^2 and replace the result in the initial equation as:

x^2+3x+4=(x+a)^2+b\\x^2+3x+4=x^2+2ax+a^2+b

Then, this equality apply only if the coefficient of x is equal in both sides and the constant is equal in both sides.

It means that we have two equations:

3x=2ax\\4=a^2+b

So, using the first equation and solving for a, we get:

3x=2ax\\3=2a\\a=\frac{3}{2}=1.5

Finally, replacing the value of a in the second equation and solving for b, we get:

4=a^2+b\\4=1.5^2+b\\b=4-1.5^2\\b=4-2.25\\b=1.75

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3 years ago
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Say something nice about me
Kruka [31]

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Step-by-step explanation:

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Solve the system by using a matrix equation (Picture provided)
Katyanochek1 [597]

Answer:

Option b is correct (8,13).

Step-by-step explanation:

7x - 4y = 4

10x - 6y =2

it can be represented in matrix form as\left[\begin{array}{cc}7&-4\\10&-6\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}4\\2\end{array}\right]

A= \left[\begin{array}{cc}7&-4\\10&-6\end{array}\right]

X= \left[\begin{array}{c}x\\y\end{array}\right]

B= \left[\begin{array}{c}4\\2\end{array}\right]

i.e, AX=B

or X= A⁻¹ B

A⁻¹ = 1/|A| * Adj A

determinant of A = |A|= (7*-6) - (-4*10)

                                    = (-42)-(-40)

                                    = (-42) + 40 = -2

so, |A| = -2

Adj A=  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]

A⁻¹ =  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]/ -2

A⁻¹ =  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right]

X= A⁻¹ B

X=  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right] *\left[\begin{array}{c}4\\2\end{array}\right]

X= \left[\begin{array}{c}(3*4) + (-2*2)\\(5*4) + (-7/2*2)\end{array}\right]

X= \left[\begin{array}{c}12-4\\20-7\end{array}\right]

X= \left[\begin{array}{c}8\\13\end{array}\right]

x= 8, y= 13

solution set= (8,13).

Option b is correct.

3 0
3 years ago
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