I don’t understand u sorry ;-;
you find what they both divide by and then divide each one and then you keep doing that until you cant no more
Step-by-step explanation:
The average speed is distance over time.
34 mi / 0.5 hr = 68 mph
Therefore, the driver must have been speeding at some point between the two toll booths.
Answer:
1st box: Asso. prop= m+(4+x)
2nd box: Comm. Prop= m+4=4+m
3rd box: iden. prop= m+0=m
4th box: Zero prop: m x 0=0
