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exis [7]
3 years ago
11

A scuba diver descends at a constant rate of 8feet per minute

Mathematics
1 answer:
Dmitrij [34]3 years ago
7 0
Yes. I agree, much question.
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The radius of the circle - shaped poster is 9 inches. What is the approximate circumference?
statuscvo [17]

Answer: 56.55inch

Step-by-step explanation:

Circumference formula: C = 2\pi r

C = 2(3.1416)(9inch)

C= 56.55inch

5 0
3 years ago
The equation below is a horizontal line. y = −4<br><br> true? or<br> false?
777dan777 [17]

Answer:

That is true. If you graph y=-4 it would be a horizontal line on the y axis


Step-by-step explanation:


5 0
3 years ago
Read 2 more answers
I need help<br> If you know this answer plz give it ta meh
Oksana_A [137]

Answer:

4.9 units

Step-by-step explanation:

We are dealing with a Right angle triangle, and the c is actually the hypotenuse. We are given the measures of a and b.

a being 4, and b being 3.

We need to use the Pythagorean Theorem to solve this.

a^2 + b^2 = c^2

we can rewrite this as;

4^2 + 3^2 = c^2\\

Calculation time

15 + 9 = c

c = 24

Now we find the square root of each equation to determine what c^2 is.

\sqrt{15}+\sqrt{9}=\sqrt{24}

4 + 3 = 4.89897948557

Let's round that to the nearest tenth.

4.9 units

Hope this helped :)

3 0
2 years ago
Read 2 more answers
Length and width of a soccer field?
djyliett [7]

Answer:

50-100 yards in width and 100-130 yards in length

Step-by-step explanation:

7 0
2 years ago
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For a population with µ = 80 and σ = 20, the Sampling distribution of the Mean, based on n = 16 will have an expected value of t
allsm [11]

Answer:

Will have an expected value of the mean = 80 and a standard error of the mean = 5

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 80, \sigma = 20

n = 16

So the mean is 80 and the standard deviation is s = \frac{20}{\sqrt{16}} = 5

Will have an expected value of the mean = 80 and a standard error of the mean = 5

6 0
3 years ago
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