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3 years ago

Put them in the order from least to greatest. You can use the number line to help.

Mathematics

1 answer:

notka56 [123]3 years ago

8 0

Answer:

-1.85 -7/8 1 3/4

Step-by-step explanation:

It is about which one is to the farest right ▶️ from 0

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Find the product.

4vir4ik [10]

Answer :

$6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3 {y}^{3} {z}+3 {y}^{2} {z}^{2}$

Step-by-step explanation :

To find the product of

$3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)$

First we expand the bracket ,

it implies that, we use the expression outside the bracket to multiply individual expressions inside the bracket.

Hence

$3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)$

$= 3 {y}^{2} z(2 {y}^{2} z) + 3 {y}^{2} z(4yz) - 3 {y}^{2} z(y )+3 {y}^{2} z( z)$

we now apply the law of indices

${a}^{m} \times {a}^{n} = {a}^{m+n}$

meaning, when you are multiplying two expressions with the same bases , repeat one of the bases and add the exponents.

Then, simplify to obtain

$= 6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3{y}^{3} {z}+3 {y}^{2} {z}^{2}$

3 0

3 years ago

A rectangular gasoline tank can hold 45.0 kg of gasoline when full. what is the depth of the tank if it is 0.450 m wide by 0.900

garri49 [273]

The answer is 0.154 m

Step 1. Calculate the volume of gasoline tank (V) using the known mass (m) and density of gasoline (D).
D = m/V
⇒ V = m/D
D = 719.7 kg/m³
m = 45.0 kg
V = 45.0 kg/719.7 kg/m³ = 0.0625 m³

Step 2. Calculate the depth of the tank (d) using the known volume (V) of gasoline and width (w) and length (l) of the tank:
V = d * w * l
0.0625 = d * 0.900 * 0.450
0.0625 = d * 0.405
d = 0.0625 / 0.405
d = 0.154 m

7 0

3 years ago

Which ordered pair is a solution to the system of inequalities

Mademuasel [1]

Answer:

Step-by-step explanation:

i took the test

8 0

3 years ago

(2y+3)(3y^2+4y+5) use the chart to multiply the binomial by the trinomial

astra-53 [7]

(2y+3)(3y^2+4y+5)

so u just multiply all the things from different brackets.

2y*3y^2 = 6y^3

2y*4y = 8y^2

2y*2 = 4y

3*3y^2 = 9y^2

3*4y = 12y

3*5 = 15

so 6y^3+8y^2+4y+9y^2+12y+15

thats the answer BUT u need to collect the like terms, otherwise u probably wont get full marks on the question, so:

6y^3+17y^2+16y+15

i hope this helps :)

someone correct me if im wrong

8 0

3 years ago

Find the solutions to the equation. Select ALL that apply.

alisha [4.7K]

Answer:

Step-by-step explanation:

-3y(2y+5)=0

-6y+15y=0

9y=0

y=0÷9

y=0

5 0

3 years ago