Answer:
A function that gives the work required in foot-lbs to lift the bucket up x feet from the ground is 
and the work to get the bucket to the top of the cliff is 3726 foot-lbs
Step-by-step explanation:
Work done to lift the rope by distance x feet:
Work done to lift the bucket by distance x feet:
On reaching top 7 gallons of water spilled out so , on going up by x feet 
gallons of water spilled out.
a function that gives the work required in foot-lbs to lift the bucket up x feet from the ground:
Now the work to get the bucket to the top of the cliff i.e. x =35
W=3726
Hence, a function that gives the work required in foot-lbs to lift the bucket up x feet from the ground is and the work to get the bucket to the top of the cliff is 3726 foot-lbs
Answer:
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
Step-by-step explanation:
Hello!
Considering the dependent variable:
Y: Ductility in steel.
And the independent variable:
X: Carbon content of the steel.
The linear regression was estimated and a prediction interval was calculated.
The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=
]
In this case 95% prediction interval for Y/X=0.5
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
I hope it helps!
-1 and 1/3 because you convert to a regular fraction and get (32/9)/(-8/3), then you flip the fraction and multiply
Answer:
c
Step-by-step explanation:
