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lana [24]
3 years ago
8

The circule by X^2 + Y^2- 2y-11=0

Mathematics
1 answer:
Sati [7]3 years ago
5 0
X^2 + y^2 -2y-11=0

x^2 + y^2 -2y=11

x^2 + y^2 -2y + ? = 11 + ?

x^2 + y^2 -2y + 1 = 11 + ?

x^2 + y^2 -2y + 1 = 11 + 1

x^2 + (y-1)^2 = 12

Solution: Circle
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one factor of f(c) = 5x3 + 5x2 - 170x + 280 is (x + 7). What are all the roots of the function? Use the remainder theorem
elena55 [62]

Answer:

So the roots of the polynomial are -7 , 4 , 2

Step-by-step explanation:

Given the polynomial in the question

5x³ + 5x² - 170x + 280

One of the factor of this polynomial is (x + 7)

By using remainder theorem

          5x²-30x+40

       -----------------------------------

x+7 | 5x³ + 5x² - 170x + 280

        5x³ + 35x²

               ----------------------------

                  -30x² -170x + 280

                  -30x² -210x

                            ------------------

                              40x + 280

                              40x + 280

                              ----------------

                                             0

So the polynomial we have is  

5x²- 30x + 40

divide by 5

x² - 6x + 8

(x-4)(x-2)

So the roots of the polynomial are -7 , 4 , 2

   

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Step-by-step explanation:

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