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lana [24]
4 years ago
8

The circule by X^2 + Y^2- 2y-11=0

Mathematics
1 answer:
Sati [7]4 years ago
5 0
X^2 + y^2 -2y-11=0

x^2 + y^2 -2y=11

x^2 + y^2 -2y + ? = 11 + ?

x^2 + y^2 -2y + 1 = 11 + ?

x^2 + y^2 -2y + 1 = 11 + 1

x^2 + (y-1)^2 = 12

Solution: Circle
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Step-by-step explanation:

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Ratling [72]

Answer:

The answer to your question is ∠ABE = 46

Step-by-step explanation:

Data

BE is a bisector of ∠ABE

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Process

1.- Bisector is a line that divides an angle into two equal angles.

So

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3.- Solve for x

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