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lana [24]
3 years ago
8

The circule by X^2 + Y^2- 2y-11=0

Mathematics
1 answer:
Sati [7]3 years ago
5 0
X^2 + y^2 -2y-11=0

x^2 + y^2 -2y=11

x^2 + y^2 -2y + ? = 11 + ?

x^2 + y^2 -2y + 1 = 11 + ?

x^2 + y^2 -2y + 1 = 11 + 1

x^2 + (y-1)^2 = 12

Solution: Circle
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Answer:

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Step-by-step explanation:

1. since a and c share the same squareroot x, you can combine these together.

2. First add like terms together. 4m - m + 6m = 9m. Then 5\sqrt{n} and -3\sqrt{n} combined equals 2\sqrt{n}

3. First simplify the square roots. squareroot of 16 is 4. square root of 49 is 7. square root of 81 is 9. They are all multiplied by a in the expression. Thus 4a - 7a + 9a = 6a

4. First simplify the radicals, they are not perfect. square root of 125 is equivalent to sqrt(25 * 5), which sqrt of 25 is 5, but we keep the sqrt of 5. For sqrt of 45, it is the same as sqrt9 * sqrt5. sqrt of 9 is the same as 3 and we keep sqrt 5. Thus we get the below:

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3 years ago
Solve the inequality 16 > -2u
Ksju [112]
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dsp73

Answer:

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Step-by-step explanation:

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