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lana [24]
3 years ago
8

The circule by X^2 + Y^2- 2y-11=0

Mathematics
1 answer:
Sati [7]3 years ago
5 0
X^2 + y^2 -2y-11=0

x^2 + y^2 -2y=11

x^2 + y^2 -2y + ? = 11 + ?

x^2 + y^2 -2y + 1 = 11 + ?

x^2 + y^2 -2y + 1 = 11 + 1

x^2 + (y-1)^2 = 12

Solution: Circle
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Solve for k.<br> 6k - 8 = 4K + 15
Brut [27]

Hi,

Answer:

k = \frac{23}{2}

Step-by-step explanation:

Subtract 4k from both sides

6k - 4k = 2k

2k - 8 = 15

Add 8 on both sides (you want to get rid of the 8 in order to leave the k alone)

2k = 23

k = 23/2

Have a good day!

4 0
3 years ago
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Murrr4er [49]
1/9 - 5/6

Convert both of them into denominators of 18.

2/18 - 15/18

Subtract the numerators and keep the denominator:

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3 0
3 years ago
Can someone help me learn to do ratios. I'm in 6th grade and I was absent during the lesson. I'm afraid ill fail if I don't lear
marin [14]

Answer:  24: 80

Step-by-step explanation: 6 can go into 24 4 times. So if we do the same for 20 it will be 20 times 4. Hence, answer is 24:80

7 0
3 years ago
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Diego and Lin are drinking milkshakes. Lin starts with 12 ounces and drinks 1/4 an ounce per second. Diego starts with 20 ounces
sammy [17]

Answer:

Lin = 48 seconds  

Diego = 30 seconds  

Step-by-step explanation:

Hi, to answer this question we have to divide the total ounces of drink by the amount that each one drank per second, for each case.

Mathematically speaking:

Lin = 12 ounces / (1/4) ounces/second = 12/ (1/4) = 48 seconds  

Diego = 20 ounces / (2/3) ounces/second = 20/ (2/3) = 30 seconds  

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3 0
3 years ago
I NEED HELP!!!
andrey2020 [161]

Answer:

<h2>B. The amount of fuel used was lowest at speeds around 60km/h.</h2>

Step-by-step explanation:

The decreasing part is from (20,13) to (60,6), which gives an average rate of

r=\frac{6-13}{60-20}=-\frac{7}{40}=-0.175

Then, we have an increasing part from (60,6) to (120,10), which gives an average rate of

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Basically, at 60 km/h the fuel used was 6 liters per 100 kilometers. Notice that the other velocities make the car to use more liters per kilometers.

Therefore, the amount of fuel used was lowest at speeds around 60 km/h.

6 0
3 years ago
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