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Whitepunk [10]
3 years ago
13

A ball is kicked upward with an initial velocity of 52 feet per second. The ball's height, h (in feet), from the ground is model

ed by 4072-03-02-07-00_files/i0130000.jpg, where t is measured in seconds. How much time does the ball take to reach its highest point? What is its height at this point?
a.
1.625 sec; 84.5 ft

c.
3.25 sec; 42.25 ft

b.
1.625 sec; 42.25 ft

d.
3.25 sec; 126.75 ft
Mathematics
1 answer:
polet [3.4K]3 years ago
7 0
The maximum vertical distance should be calculated through the equation,
                                d = (Vf² - Vi²) / 2a
Where Vf is the final veloity, Vi is the initial velocity and a is the acceleration due to gravity (32.1740 ft/s²). Substituting the known values,
                               d = (0 - 52²) / 2(-32.1740 ft/s²) 
                                     d = 42.02 ft
The time it will take for ball to travel this distance is calculated through the equation,
                                   d = (Vo)(t) - 0.5gt²
Substituting the known values.
                                    d = (52)(t) - 0.5*32.1740t²
The value of time is 1.60 s. Thus, the nearest answer to this item is answer B. 
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Answer:

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Step-by-step explanation:

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tan θ = Opposite/Adjacent

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Hence,

tan θ = 220/100

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2 years ago
A public swimming pool that holds 45,000 gallons of water is going to be drained for maintenance at a rate of 100 gallons per mi
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Answer:

450 minutes

Step-by-step explanation:

Given

w = 45000 - 100t

Required

Determine how long it'll take to empty the pool

Being empty means there's no water in the pool.

So, we have to set w to 0 to get the value of t

i.e w = 0

Substitute 0 for w in w = 45000 - 100t

0 = 45000 - 100t

Collect Like Terms

100t = 45000

Divide through by 100.

t = 450

Hence, it'll take 450 minutes to empty the pool

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