A ball is kicked upward with an initial velocity of 52 feet per second. The ball's height, h (in feet), from the ground is model
ed by 4072-03-02-07-00_files/i0130000.jpg, where t is measured in seconds. How much time does the ball take to reach its highest point? What is its height at this point? a.
1.625 sec; 84.5 ft
The maximum vertical distance should be calculated through the equation, d = (Vf² - Vi²) / 2a Where Vf is the final veloity, Vi is the initial velocity and a is the acceleration due to gravity (32.1740 ft/s²). Substituting the known values, d = (0 - 52²) / 2(-32.1740 ft/s²) d = 42.02 ft The time it will take for ball to travel this distance is calculated through the equation, d = (Vo)(t) - 0.5gt² Substituting the known values. d = (52)(t) - 0.5*32.1740t² The value of time is 1.60 s. Thus, the nearest answer to this item is answer B.
