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nasty-shy [4]
3 years ago
10

A spherical mini donut hole has a diameter of 6 centimeters. A large spherical donut hole has a diameter of 9 centimeters. Appro

ximately how much greater is the volume of a large donut hole than the volume of a mini donut hole?
86 cm³

113 cm³

226 cm³

268 cm³
Mathematics
2 answers:
Novay_Z [31]3 years ago
8 0
I think its 113......
Archy [21]3 years ago
5 0

Solution:

we are given that

A spherical mini donut hole has a diameter of 6 centimeters.

A large spherical donuts hole has a diameter of 9 centimetres.

we have been asked to find

Approximately how much greater is the volume of a large donuts hole than the volume of a mini donuts hole?

As we know the volume of the sphere is given by the formula

V=\frac{4}{3} \pi r^3\\ \\ \text{So volume of smaller Spherical(r=6/2=3) hole can be given as }\\ \\ V_1= \frac{4}{3} \pi *3^3\\ \\ \text{So volume of larger Spherical hole(r=9/2=4.5) can be given as }\\ \\ V_1= \frac{4}{3} \pi *4.5^3\\ \\ \text{So Difference in volume}=\frac{4}{3} \pi *4.5^3-\frac{4}{3} \pi *3^3\\ \\ \text{Simplify we get}\\ \\ \text{So Difference in volume} \approx 268 cm^3\\ \\

Hence the correct option is 268 cm^3

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Probability of a student playing both basketball and baseball is 7/28

Step-by-step explanation:

Step 1:

It is given the class has 28 students out of which 11 play basketball and 13 play baseball. It is also given that 11 students play neither sport.

Total number of students = 28

Students playing neither sport = 11

Students playing at least one sport = 28 - 11 = 17

Step 2:

Let N(Basketball) denote the number of students playing  basketball and N(Baseball) denote the number of people playing  baseball.

Then N(Basketball U Baseball) denotes the total number of students playing basketball and baseball and N(Basketball ∩ Baseball) denotes playing both basketball and baseball.

Since the number of students playing at least one sport is 17, N (Basketball U Baseball) = 17.

N (Basketball U Baseball) = N(Basketball) + N(Baseball) - N(Basketball ∩ Baseball)

N(Basketball ∩ Baseball) = N(Basketball) + N(Baseball) - N (Basketball U Baseball)

N(Basketball ∩ Baseball) = 11 + 13 - 17 = 7

Step 3:

Number of students playing both basketball and baseball = 7

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Probability of a student playing both basketball and baseball is 7/28

Step 4:

Answer:

Probability of a student playing both basketball and baseball is 7/28

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