B and C are both x-intercepts
An x-intercept occurs anywhere that a line or point touches the x-axis while y=0. With these answer choices, B and C are both values that happen on the x-axis, while y is equaling 0.
f(x) = sqrt [( x - 3) / (x - 5)]
well x cannot be 5 because that would make x - 5 = 0.
Also the fraction x - 3 / x - 5 cannot be negative because theres no real square root of a negative.
So x must be <= 3 or > 5
In interval notation the domain is ( -∞,3] or (5 , ∞)
Answer:
a
Step-by-step explanation:
Let 11x + 15y + 23 = 0 be equation (1)
And 7x - 2y - 20 = 0 be equation (2)
Multiply equation (1) by 2:
22x + 30y + 46 = 0
Multiply equation (2) by 15:
105x - 30y - 300 = 0
Add equations (1) and (2):
22x + 105x + 30y - 30y + 46 - 300 = 0
127x - 254 = 0
127x = 254
x = 254/127
[x = 2]
Substitute x = 2 in equation (1) to find y:
11(2) + 15y + 23 = 0
22 + 15y + 23 = 0
15y + 45 = 0
15y = -45
y = -45/15
y = -3
Therefore, x = 2 and y = -3.