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3 years ago

What is the slope of the line that goes through the points (1,-5) and (4,1)?

2 answers:

5 0

Vas Happenin!
Hope your day is going well
Slope form is y2-y1/x2-x1
Y2= 1
Y1 = -5
X2= 4
X1 = 1
Then you plug them into the equation it should look like this
1 - -5/ 4-1
Then you subtract them
6/3
Then you divide
Your slope is 2 m=2
Hope this helps *smiles*

V125BC [204]3 years ago

3 0

Answer:

The slope is 2

Step-by-step explanation:

The Slope formula is y2-y1/x2-y1.

1. Plug the numbers into the slope equation which is 1-(-5)/4-1=2

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2. In how many ways can 3 different novels, 2 different mathematics books and 5 different chemistry books be arranged on a books

insens350 [35]

The number of ways of the books can be arranged are illustrations of permutations.

When the books are arranged in any order, the number of arrangements is 3628800
When the mathematics book must not be together, the number of arrangements is 2903040
When the novels must be together, and the chemistry books must be together, the number of arrangements is 17280
When the mathematics books must be together, and the novels must not be together, the number of arrangements is 302400

The given parameters are:

$\mathbf{Novels = 3}$

$\mathbf{Mathematics = 2}$

$\mathbf{Chemistry = 5}$

(a) The books in any order

First, we calculate the total number of books

$\mathbf{n = Novels + Mathematics + Chemistry}$

$\mathbf{n = 3 + 2 + 5}$

$\mathbf{n = 10}$

The number of arrangement is n!:

So, we have:

$\mathbf{n! = 10!}$

$\mathbf{n! = 3628800}$

(b) The mathematics book, not together

There are 2 mathematics books.

If the mathematics books, must be together

The number of arrangements is:

$\mathbf{Maths\ together = 2 \times 9!}$

Using the complement rule, we have:

$\mathbf{Maths\ not\ together = Total - Maths\ together}$

This gives

$\mathbf{Maths\ not\ together = 3628800 - 2 \times 9!}$

$\mathbf{Maths\ not\ together = 2903040}$

(c) The novels must be together and the chemistry books, together

We have:

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the novels in:

$\mathbf{Novels = 3!\ ways}$

Next, arrange the chemistry books in:

$\mathbf{Chemistry = 5!\ ways}$

Now, the 5 chemistry books will be taken as 1; the novels will also be taken as 1.

Literally, the number of books now is:

$\mathbf{n =Mathematics + 1 + 1}$

$\mathbf{n =2 + 1 + 1}$

$\mathbf{n =4}$

So, the number of arrangements is:

$\mathbf{Arrangements = n! \times 3! \times 5!}$

$\mathbf{Arrangements = 4! \times 3! \times 5!}$

$\mathbf{Arrangements = 17280}$

(d) The mathematics must be together and the chemistry books, not together

We have:

$\mathbf{Mathematics = 2}$

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the mathematics in:

$\mathbf{Mathematics = 2!}$

Literally, the number of chemistry and mathematics now is:

$\mathbf{n =Chemistry + 1}$

$\mathbf{n =5 + 1}$

$\mathbf{n =6}$

So, the number of arrangements of these books is:

$\mathbf{Arrangements = n! \times 2!}$

$\mathbf{Arrangements = 6! \times 2!}$

Now, there are 7 spaces between the chemistry and mathematics books.

For the 3 novels not to be together, the number of arrangement is:

$\mathbf{Arrangements = ^7P_3}$

So, the total arrangement is:

$\mathbf{Total = 6! \times 2!\times ^7P_3}$

$\mathbf{Total = 6! \times 2!\times 210}$

$\mathbf{Total = 302400}$

Read more about permutations at:

brainly.com/question/1216161

8 0

2 years ago

Find the imaginary solutions to the following quadratic function:

Temka [501]

Answer:

the solutions are these

Step-by-step explanation:

$\frac{3}{14} + \frac{ \sqrt{159} }{14} i \: and \\ \: \frac{3}{14} - \frac{ \sqrt{159} }{14} i$

8 0

3 years ago

which of the following equation represent the amount of money annalise earns y in a week based on the number of hours x she work

il63 [147K]

I think that the answer is 24 or 32 because of the longitude of that cirlce

4 0

3 years ago

Please help me with this question

Korolek [52]

Hope you have got the answer to this question. If not, here it is:
(a² -b²) +(a+b)
(a+b)(a-b)+(a+b)
(a+b)(a-b+1)

5 0

3 years ago

What is the probability of having 53 Mondays in a leap year?

Ronch [10]

Answer:

1/7

Step-by-step explanation:

There are 52 weeks in a year. Each have one Monday. Leap years have a total of 366 days. There are 7 days of the week. Monday is one of them, so it'll be a 1/7 chance.

5 0

4 years ago