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joja [24]
3 years ago
6

Can someone please help meee

Mathematics
2 answers:
Vesna [10]3 years ago
8 0

Answer:

option 3

Step-by-step explanation:

all other angles are  interior and exterior

olasank [31]3 years ago
4 0

Answer:

top right.

Step-by-step explanation:

you're looking for the inner angles on opposite sides. so one angle is facing one way while the other angle is facing the opposite direction, while being located between the parallel lines

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How do you illustrate quadratic equation in one varible?<br>​
kvasek [131]

Answer:

A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared. The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable. One absolute rule is that the first constant "a" cannot be a zero.

Step-by-step explanation:

6 0
3 years ago
Fortninte.com had 595,760 visitors in June 2018, and 615,355 in July 2018. How many more visitors came in July than June?
Inessa [10]

Solve. Subtract July 2018 with June 2018

615355 - 595760 = 19595

19595 more people visited Fortnite's website in July than June.

hope this helps

<em>~Rise Above the Ordinary</em>


6 0
2 years ago
Read 2 more answers
Suppose X has an exponential distribution with mean equal to 23. Determine the following:
e-lub [12.9K]

Answer:

a) P(X > 10) = 0.6473

b) P(X > 20) = 0.4190

c) P(X < 30) = 0.7288

d) x = 68.87

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Mean equal to 23.

This means that m = 23, \mu = \frac{1}{23} = 0.0435

(a) P(X >10)

P(X > 10) = e^{-0.0435*10} = 0.6473

So

P(X > 10) = 0.6473

(b) P(X >20)

P(X > 20) = e^{-0.0435*20} = 0.4190

So

P(X > 20) = 0.4190

(c) P(X <30)

P(X \leq 30) = 1 - e^{-0.0435*30} = 0.7288

So

P(X < 30) = 0.7288

(d) Find the value of x such that P(X > x) = 0.05

So

P(X > x) = e^{-\mu x}

0.05 = e^{-0.0435x}

\ln{e^{-0.0435x}} = \ln{0.05}

-0.0435x = \ln{0.05}

x = -\frac{\ln{0.05}}{0.0435}

x = 68.87

5 0
3 years ago
7(3r - 1) - (r + 5) = -52<br><br> Please step by step help
MrMuchimi
7(3r-1)-(r+5)=-52

21r-7-r-5=-52

21r-r-5-7=-52

20r-12=-52

Add 12 to both sides

20r=-40

Divide by 20

r=-2
4 0
3 years ago
Read 2 more answers
Pls do with the working
saveliy_v [14]

Answer:

2) 70,000

Step-by-step explanation:

since they have said estimate meaning frist round off

679 rounds up to 700 and 98 rounds up to 100

700×100

70000

4 0
2 years ago
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