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2 years ago

Six times a number is 45 greater than the product of the number and -3. Find the number.

Mathematics

1 answer:

LiRa [457]2 years ago

8 0

Answer:

Step-by-step explanation:

6a = (a*-3) + 45

then:

6a = -3a + 45

6a + 3a = 45

9a = 45

a = 45/9

a = 5

Check:

6*5 = (5*-3) + 45

30 = -15 + 45

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Answer:

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Step-by-step explanation:

Given that'

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Mean (m) = 29.6

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Consider the given fraction $\frac{x^3-x^2}{x^3}$

We have to reduce the fraction to the lowest terms.

Consider numerator $x^3-x^2$

We can take x² common from both the term,

Thus, numerator can be written as $x^2(x-1)$

Given expression can be rewritten as ,

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