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VMariaS [17]
3 years ago
8

Will give brainliest thanks :)

Mathematics
2 answers:
iren [92.7K]3 years ago
8 0
A straight line is 180 degrees. So, since the line bisects (or splits the straight line in 2) angle 1 and angle 2 add up to equal 180 degrees.
So, to find angle 2, subtract 139 degrees from 180 to get the second angle, which would be 41 degrees
frozen [14]3 years ago
6 0
2 would equal to 41 because since its a straight line you would do 180-139 and get 41. Have a good day and ask questions!! :)

-Kaylie

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A scale model of a tower is 24 inches tall and 18 inches wide. If the height of the actual tower is 60 feet, what is its width?
alex41 [277]

Answer:

45 feet

Step-by-step explanation:

To find the width of the model, we need to find the scale of the model to the actual tower.

Since we know the height of both towers, we can use that as the basis.

24 inches : 60 feet

12 inches : 30 feet

6 inches : 15 feet

So the width of the tower is 18 inches wide.

18 inches will then be equal to 12 + 7 inches : 30 + 15 feet

18 inches : 45 feet

6 0
3 years ago
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Answer:

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3 0
3 years ago
Write the equation of a line that passes through points (-3,2)(-9,-8)
ollegr [7]

Answer:

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6 0
3 years ago
Justify each step. <br> x/3-7=11 <br> x/3=18<br> x=6
Nina [5.8K]
This is the steps for equation solving for the value of x,
x/3-7 = 11
now 7 goes to the other side of equation by changing the sign from - to +,
x/3 = 11 + 7
x/3 = 18
now when we multiply both sides of equation with 3 or 3 goes to the other side of equation and multiply with 18 leaving x alone here for finding the value of x,
and we get, x = 54
at the end of equation we get x = 54, if the equation was in the form 3x - 7 = 11, then we will get x = 6
8 0
3 years ago
What is the value of sec theta given the diagram below?
marishachu [46]

Answer:

\sec \theta=-\sqrt{5}

Step-by-step explanation:

The hypotenuse is h^2=6^2+3^2

h^2=36+9

h^2=45

h=\sqrt{45}

h=3\sqrt{5}

The terminal side of \theta is in the second quadrant.

In this quadrant; the secant ratio is negative.

\sec \theta=-\frac{hypotenuse}{adjacent}

\sec \theta=-\frac{3\sqrt{5}}{3}

\sec \theta=-\sqrt{5}

6 0
3 years ago
Read 2 more answers
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