Alright, here it is w=(q+p)/(q-pq) factor out the q in the bottom part
w=(q+p)/[(q)(1-p)] multiply both sides by q wq=(q+p)/(1-p) add 1 to both sides, but add (1-p)/(1-p) to the right side since that equals 1 wq+1=(q+1+p-p)/(1-p)=(q+1)/(1-p) multiply both sdies by (1-p) (wq+1)(1-p)=q+1 divide both sdies by (wq+1) 1-p=(q+1)/(wq+1) subtract 1 from both sdies -p=[(q+1)/(wq+1)]-1 multiply by -1 p=-[(q+1)/(wq+1)]+1 or
Remove the extra parentheses<span>. </span><span>w=<span><span>q+p/</span><span>q−qp
</span></span></span>Since p<span> is on the right-hand side of the </span>equation<span> switch the sides so it is on the left-hand side of the </span>equation<span>. </span><span><span><span>q+p/</span><span>q−qp</span></span>=w
</span>Factor q<span> out of </span><span><span>q−qp</span>.</span><span> </span><span><span><span>q+p/</span><span>q⋅(1−1p)</span></span>=w</span>
Rewrite <span>−1p</span><span> as </span><span><span>−p</span>.</span><span> </span><span><span><span>q+p/</span><span>q⋅(1−p)</span></span>=w</span> <span>
</span>Multiply q<span> by </span><span>1−p</span><span> to get </span><span><span>q(1−p)</span>. </span><span><span><span>q+p/</span><span>q(1−p)</span></span>=w </span> Multiply<span> each </span>term<span> in the </span>equation<span> by </span><span><span>(1−p)</span>. </span><span><span><span>q+p/</span><span>q(1−p)</span></span>⋅(1−p)=w⋅(1−p)</span><span> </span> <span>1+<span>p/q</span>=w−wp</span>
Since <span>−wp</span><span> contains the </span>variable<span> to solve for, move it to the left-hand side of the </span>equation<span> by adding </span><span>wp</span><span> to both sides. </span><span>1+<span>p/q</span>+wp=w </span> Find the LCD<span> of the </span>terms<span> in the </span>equation<span>. </span>It is <span>q
</span>Multiply<span> each </span>term<span> in the </span>equation<span> by </span>q<span> in order to remove all the </span>denominators<span> from the </span>equation<span>. </span><span>p+wpq=−q+wq
</span>Solve the equation<span>. </span>p=<span><span>q(w−1)/</span><span>qw+1