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nikitadnepr [17]
3 years ago
6

a rectangle is 5cm longer than its breadth, its perimeter is 26 find the length and breadth of the rectangle​

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
5 0
If the perimeter is 26 and the length of one side of the rectangle is 5cm longer than its breadth,

26 - 5 - 5 = 16
16 / 4 = 4 ( rectangle has 4 sides. )

the breadth is 4cm.
so the length must be 4+5=9cm.
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A cup of coffee has approximately 310 mg of caffeine. Each hour, the caffeine in your system decreases by about 35%. How much ca
Alex787 [66]

Answer:

∴35.97 mg caffeine would be left in the system after 5 hours.

Step-by-step explanation:

Given that,

A cup of coffee has approximately 310 mg of caffeine.

Caffeine decrease at a rate 35% per hour.

Exponential Function:

y(t)=y_0(1-r)^t

y(t)= Amount caffeine after t hours

y_0= Initial amount of caffeine

r= rate of decrease

t = Time in hour.

Here y(t)=?, y_0 = 310 mg, r=35%=0.35, t= 5 hours

y(t)=310(1-0.35)^5

      =35.97 mg

∴35.97 mg caffeine would be left in the system after 5 hours.

3 0
4 years ago
Take away 2 from 7 times h
yan [13]

Answer:7h-2

Step-by-step explanation:

take away 2 indicates -2

7 times h indicates 7h

then you have a few ways to write this out either: -2+7h or 7h-2

both are correct!

3 0
3 years ago
A manufacturer has been selling 1000 flat-screen TVs a week at $500 each. A market survey indicates that for A manufacturer has
luda_lava [24]

Answer:

a) Demand function: q=6000-10\cdot p

b) The rebate should be of $200, so the sale price becomes $300 per unit.

c) The rebate should be of $150, so the sale price becomes $350 per unit.

Step-by-step explanation:

a) In this case, we have a known point of the demand function (1000 units sold at $500), and the slope of a linear function (increase by 100 units fora decrease in $10).

We can express the demand function (linear) as:

q=b+m\cdot p

To calculate the slope m, we use:

m=\Delta q/\Delta p=(+100)/(-10)=-10

To calculate b, we use the known point and the calculated slope:

q=b+m\cdot p\\\\b=q-m\cdot p=1000-(-10)\cdot (500)=1000+5000=6000

Then the demand function is:

q=6000-10\cdot p

b) The revenue can be expressed as:

R=q\cdot p = (6000-10p)\cdot p=6000p-10p^2

To maximize, we can derive and equal to zero

dR/dp=6000-2*10p=0\\\\20p=6000\\\\p=300

The rebate should be of $200, so the sale price becomes $300 per unit.

c) If we take into account the cost, we have that

R=q\cdot p-C=(6000p-10p^2)-(68000+100q)\\\\R=(6000p-10p^2)-(68000+100(6000-10p))\\\\R=6000p-10p^2-(68000+600000-1000p)\\\\R=-10p^2+7000p-668000

To maximize, we can derive and equal to zero

dR/dp=-20p+7000=0\\\\p=7000/20=350

The rebate should be of $150, so the sale price becomes $350 per unit.

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Answer:

If sin 49° = cos 41°

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A) is 0.83 and idk how to do b)
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