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avanturin [10]
3 years ago
10

There are 12 feet of wrapping paper on each roll. Jill needs 84 feet of wrapping paper. Which equation can Jill use to find the

number of rolls, r, she needs?
Mathematics
2 answers:
koban [17]3 years ago
8 0

Answer:

The correct answer is "All of these answers are correct."

Step-by-step explanation:

These are very simple.

12r=84 ✔

84/r=12 ✔

84/12=r ✔

All of these answers are correct ✔

postnew [5]3 years ago
6 0

Answer:

es26

Step-by-step explanation:

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Ghella [55]

Answer:

The answer is B. 1,620

Step-by-step explanation:

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Lubov Fominskaja [6]

Answer:

F = 1.8C +32

F = 86^{\circ}F

Step-by-step explanation:

Represent Celsius with C and Fahrenheit with F.

So, we have:

(C_1,F_1) = (100,212)

(C_2,F_2) = (0,32)

Solving (a): Represent as a linear equation

First, we calculate the slope:

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This gives:

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m = \frac{-180}{- 100}

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The linear equation is then calculated using:

F - F_1 = m(C -C_1)

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(C_1,F_1) = (100,212)

m = 1.8

F - 212 = 1.8(C -100)

F - 212 = 1.8C -180

Make F the subject

F = 1.8C -180+212

F = 1.8C +32

Solving (b): The value of F when C = 30

Substitute 30 for C in F = 1.8C +32

F = 1.8 * 30 + 32

F = 54 + 32

F = 86

8 0
3 years ago
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Suppose you have $10,000 to invest. Which of the two rates would yield the larger amount in 4 years. 7% compounded quarterly or
GalinKa [24]
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2)\ \ \ 6.94\%\ daily\\\\ \ \Rightarrow\ \  \frac{1}{365} \cdot6.94\% \approx0.019\%\ \ annually\ \ \Rightarrow\ \ p=0.019\\\\ daily\ \Rightarrow\  365\ times\ annually\ \Rightarrow\ 1420\ times\ in\ 4\ years\ \Rightarrow\ n=1420\\\\Sum(6.94\%)=\$10,000\cdot(1+ \frac{0.019}{100})^{1420}=\\ \\.\ \ \ \ \ \ \ \ \ \ \ \ =\$10,000\cdot(1+0,00019)^{1420}\approx\$13096.69\\---------------------------\\\$13,199.29 > \$13,096.69\\\\Ans.\ the\ larger\ amount\ gives\ the\ compounded\ quarterly.
5 0
3 years ago
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Answer:

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3 years ago
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TiliK225 [7]

Answer:

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Step-by-step explanation:

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After that, I got 11/20, which is the new first measurement.

7 0
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