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2 years ago

Plz help asap i need the right answer who ever is right get brainiest

Mathematics

1 answer:

e-lub [12.9K]2 years ago

5 0

X=18

Step-by-step explanation:

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Please help I appreciate it

Anni [7]

Answer:

Step-by-step explanation:

g(x) got smaller

A - makes it thinner

B & C - move it to the left or right

D- makes it wider

4 0

2 years ago

Read 2 more answers

Maori created this shape out of construction paper using a ruler and scissors. She made sure that all of her angles were right a

Maru [420]

Answer:

B) 48cm²

Step-by-step explanation:

find the area of the 2 rectangles

A = bh

A = 9×4

A = 36

A = bh

A = 6×2

A = 12

add them up you get 48cm²

6 0

3 years ago

Two angles are supplementary. The measure

BlackZzzverrR [31]

Answer:

57°

Step-by-step explanation:

Let's assume the measurement of the second angle is x.

so, following the problem

(2x + 9) + x = 180

2x + x = 3x

=> 3x + 9 = 180

=> 3x = 180 - 9

3x = 171

x = 171/3

x = 57°

57° is the smallest angle

5 0

2 years ago

How to solve for x and y

Minchanka [31]

Answer-

The values of x and y are 20° and 30, respectively.

Solution-

As in the given triangle all the angles are same so it must a equilateral triangle.

In an equilateral triangle all the measurements of the angles and side length are same. The measurement of the angels are 60°.

As given in the question one side length is 46, so all the side length are same.

So,

$\Rightarrow y+16=46\\\\\Rightarrow y=46-16\\\\\Rightarrow y=30$

We know that an exterior angle of a triangle is equal to the sum of the opposite interior angles. 80° is the exterior angle opposite to x and one angle of triangle at the top vertex.

$\Rightarrow 80^{\circ}=x+60^{\circ}$

$\Rightarrow x=80^{\circ}-60^{\circ}$

$\Rightarrow x=20^{\circ}$

Therefore, the values of x and y are 20° and 30, respectively.

4 0

2 years ago

I need help solving this trig problem w/ identites.

Charra [1.4K]

$\bf sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\\\
tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}\qquad \qquad sec(\theta)=\cfrac{1}{cos(\theta)}
\\\\
-------------------------------$

$\bf \cfrac{1}{sin(x)-1}+\cfrac{1}{sin(x)+1}\implies \cfrac{sin(x)+1~~+~~sin(x)-1}{[sin(x)-1][sin(x)+1]}
\\\\\\
\cfrac{2sin(x)}{\stackrel{\textit{difference of squares}}{sin^2(x)-1^2}}\implies \cfrac{2sin(x)}{sin^2(x)-1}\implies \cfrac{2sin(x)}{-[~1-sin^2(x)~]}
\\\\\\
\cfrac{2sin(x)}{-[cos^2(x)]}\implies -2\cdot \cfrac{sin(x)}{cos(x)}\cdot \cfrac{1}{cos(x)}\implies -2tan(x)sec(x)$

3 0

3 years ago