Answer:
belongs to the line 
. Please see attachment below to know the graph of the line.
Step-by-step explanation:
From Analytical Geometry we know that a line is represented by this formula:
Where:
- Independent variable, dimensionless.
- Dependent variable, dimensionless.
- Slope, dimensionless.
- y-Intercept, dimensionless.
If we know that 
, 
and 
, then we clear slope and solve the resulting expression:
Then, we conclude that point belongs to the line , whose graph is presented below.
F(x) = x²-4x-5, quadratic function,
Domain (the values if x) is all real numbers.
To find range we should draw a graph or to write an equation in vertex form.
f(x) = x²-4x+4-4-5
f(x) = (x-2)²-9
Point (-2,-9) is the vertex of the parabola, and it is a minimum because a parabola has positive sign in front of x², so it is looking up. Minimum value of y =-9
Range(the values of y) is [-9, ∞)
Answer:
Step-by-step explanation:
Use the rise over run formula
y2-y1/x2-x1
1992-1990/3317-3038
2/-279
-139.5
So I'm assuming the answers have to be the same?? if that's the case, 457×32=15904 so you would subtract 994 from 15904. That means the answer is 14,910. I hope this helped!
