First, you combine like terms. I would start by circling the term and the sign in front of it. (A term is a piece separated by an addition/subtraction sign.) You can only combine terms with the same variable. 4.8a-2.1a-6.3b+7b is the same as your equation, just rearranged. Then, subtract (4.8a-2.1a) which is 2.7a. Add (-6.3b to 7b) The answer is 0.7b. If you have any questions, you can message me!
Answer:We must get more than 7 digs in the remaining 5 games to break record of 26.
Step-by-step explanation:
Given situation:- Let x represents the number of digs which we must get in the remaining 5 games to break your record ,and we have 19 digs for our current volleyball season.
To break previous record of 26 digs in a season, we have to get more than 26 i.e. 19 digs added to x must be greater than 26
⇒x+19 ≥ 26
⇒x≥26-19⇒x≥7
Therefore,we must get more than 7 digs in the remaining 5 games to break record of 26.
Answer:
B. The mean amount of 
emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg
Step-by-step explanation:
A Type II error is the failure to reject a false null hypothesis.
Given the null and alternate hypothesis of a fuel company which wants to test a new type of gasoline designed to have lower emissions.:
where 
is the mean amount of emitted by burning one gallon of this new gasoline.
If the null hypothesis is false, then:
A rejection of the alternate hypothesis above will be a Type II error.
Therefore:
The Type II error is: (B) The mean amount of emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg.
No 6/12 is equal to 12/24
Answer:
10-5
Step-by-step explanation:
As per the attached figure, right angled 
has an inscribed circle whose center is 
.
We have joined the incenter to the vertices of the .
Sides MD and DL are equal because we are given that 
Formula for <em>area</em> of a 
As per the figure attached, we are given that side <em>a = 10.</em>
Using pythagoras theorem, we can easily calculate that side ML = 10
Points P,Q and R are at 
on the sides ML, MD and DL respectively so IQ, IR and IP are heights of 
MIL, MID and DIL.
Also,
So, radius of circle = 
