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elena-s [515]
3 years ago
8

According to a report from the United States Environmental Protection Agency, burning one gallon of gasoline typically emits abo

ut 8.9 kg of CO2. A fuel company wants to test a new type of gasoline designed to have lower CO2 emissions. Here are their hypotheses:
H0: μ = 8.9 kg
Ha: μ < 8.9 kg (where μ is the mean amount of CO2 emitted by burning one gallon of this new gasoline).

Which of the following would be a Type II error in this setting?

A. The mean amount of CO2 emitted by the new fuel is actually 89 kg but they conclude it is lower than 89 kg
B. The mean amount of CO2 emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg
C. The mean amount of CO2 emitted by the new fuel is actual 89 kg and they alto conclude it is lower than 89 kg and they conclude it is lower than 9 kg
D. The mean amount of CO2 emitted by the new fuels actually lower than 8.9
Mathematics
1 answer:
Minchanka [31]3 years ago
8 0

Answer:

B. The mean amount of CO_2 emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg

Step-by-step explanation:

A Type II error is the failure to reject a false null hypothesis.

Given the null and alternate hypothesis of a fuel company which wants to test a new type of gasoline designed to have lower CO_2 emissions.:

H_0: \mu = 8.9 kg\\H_a: \mu < 8.9 kg \\\text{ (where \mu is the mean amount of CO_2 emitted by burning one gallon of this new gasoline)}

where \mu is the mean amount of CO_2 emitted by burning one gallon of this new gasoline.

If the null hypothesis is false, then:

H_a: \mu < 8.9 kg

A rejection of the alternate hypothesis above will be a Type II error.

Therefore:

The Type II error is: (B) The mean amount of CO_2  emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg.

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30 cm · 5 squares = 150 cm  (this is for both length and width because this quilt is a square)
For a square, perimeter=4·side, or all sides added together
p=4·150cm
p=600cm
Area of a square is length · width
A=150 cm·150 cm
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3 0
3 years ago
8. A music store sells used CDs for $9. They buy used CDs for $4. You have $50 to
Marat540 [252]

Answer: 9x+4=50

Step-by-step explanation:

In this case, we're looking at how many you can buy, not how many CD's you own.

7 0
3 years ago
Need help with this math ​
UNO [17]

Step-by-step explanation:

set up a proportion for a.

225/30=x/195. x=1462.5 milligrams daily

for b, if he gets 700 mg every 8 hours he only gets it 3 times a day. 700*3 is 2100, which means he is overdosing

7 0
3 years ago
3. A balancing balloon toy is in the shape of a hemisphere (half-sphere) attached to the base of a cone. If the toy is 4ft tall
Katen [24]

Answer:

The volume of the toy is V=5.23\ ft^3

Step-by-step explanation:

step 1

Find the volume of the hemisphere

The volume of the hemisphere is given by the formula

V=\frac{2}{3}\pi r^{3}

In this problem, the wide of the toy is equal to the diameter of the hemisphere

so

D=2\ ft

r=2/2=1\ ft ----> the radius is half the diameter

substitute

V=\frac{2}{3} \pi (1)^{3}=\frac{2}{3} \pi\ ft^3

step 2

Find the volume of the cone

The volume of the cone is given by

V=\frac{1}{3}\pi r^{2}h

we know that

The radius of the cone is the same that the radius of the hemisphere

so

r=1\ ft

The height of the cone is equal to subtract the radius of the hemisphere from the height of the toy

h=4-1=3\ ft

substitute the given values

V=\frac{1}{3}\pi (1)^{2}(3)=\pi\ ft^3

step 3

Find the volume of the toy

we know that

The volume of the toy, is equal to the volume of the cone plus the volume of the hemisphere.

so

V=(\frac{2}{3} \pi+\pi)\ ft^3

V=(\frac{5}{3}\pi)\ ft^3

assume

\pi=3.14

V=\frac{5}{3}(3.14)=5.23\ ft^3

5 0
3 years ago
Please Answer Soon!
Andru [333]

Answer:

sorry for getting it wrong

7 0
2 years ago
Read 2 more answers
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