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elena-s [515]
3 years ago
8

According to a report from the United States Environmental Protection Agency, burning one gallon of gasoline typically emits abo

ut 8.9 kg of CO2. A fuel company wants to test a new type of gasoline designed to have lower CO2 emissions. Here are their hypotheses:
H0: μ = 8.9 kg
Ha: μ < 8.9 kg (where μ is the mean amount of CO2 emitted by burning one gallon of this new gasoline).

Which of the following would be a Type II error in this setting?

A. The mean amount of CO2 emitted by the new fuel is actually 89 kg but they conclude it is lower than 89 kg
B. The mean amount of CO2 emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg
C. The mean amount of CO2 emitted by the new fuel is actual 89 kg and they alto conclude it is lower than 89 kg and they conclude it is lower than 9 kg
D. The mean amount of CO2 emitted by the new fuels actually lower than 8.9
Mathematics
1 answer:
Minchanka [31]3 years ago
8 0

Answer:

B. The mean amount of CO_2 emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg

Step-by-step explanation:

A Type II error is the failure to reject a false null hypothesis.

Given the null and alternate hypothesis of a fuel company which wants to test a new type of gasoline designed to have lower CO_2 emissions.:

H_0: \mu = 8.9 kg\\H_a: \mu < 8.9 kg \\\text{ (where \mu is the mean amount of CO_2 emitted by burning one gallon of this new gasoline)}

where \mu is the mean amount of CO_2 emitted by burning one gallon of this new gasoline.

If the null hypothesis is false, then:

H_a: \mu < 8.9 kg

A rejection of the alternate hypothesis above will be a Type II error.

Therefore:

The Type II error is: (B) The mean amount of CO_2  emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg.

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Rachel, Mario and Sanjit share some money in the ratios 4:3:9
Hoochie [10]

Answer:

£160.

Step-by-step explanation:

Mario receives 3 / (4+3+9) = 3/16 of the money.

So by proportion the total amount of money

=  96 * 16/3 = £512

So Rachel receives  4/16 = 1/4

= 512 / 4

= £128.

- and Sanjit receives 9/16

= 512 * 9/16

= £288

The difference is 288 - 128 = £160.

8 0
3 years ago
Read the following statement: Line segment MN is congruent to line segment OP.
Natasha2012 [34]

Answer:c

Step-by-step explanation:

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While working for Life magazine, Archie is assigned to the Galapagos Islands to photograph a rare, giant white turtle. The turtl
Sveta_85 [38]

Answer:

0.24

Step-by-step explanation:

From the information given:

Let's have a schematic view of a tree diagram

                                                   A

                 P(Santa Cruz)                        P(Isabella)

                  = 13/15                                    = 2/15

P(Success | Santa Cruz) = 0.09              P(Success | Isabella) = x

We are told that many have tried to locate the giant turtle, but 89% of them have failed.

This means the probability of success is:

P(success) = 1 - 0.89 = 0.11

We need to find   P(Success | Isabella),

Suppose   P(Success | Isabella) be x as shown above,

Then:

P (Success) = P(Santa) P((Success | Santa Cruz) +   P(Isabella) P(Success | Isabella)

0.11 = \dfrac{13}{15}(0.09)+ \dfrac{2}{15}(x)

0.11 - \dfrac{13}{15}(0.09)= \dfrac{2}{15}(x)

0.032= 0.133(x)

make x the subject of the formula:

x =  0.032/0.133

x = 0.24

6 0
3 years ago
A scuba diver diving with an 80 cubic foot tank of air, needs to resurface when his air in the
Burka [1]

At sea level atmospheric pressure is 1 bar absolute (1 standard atmosphere =101 kPa=1.013 bars). The weight of the atmosphere exerts a pressure which will support a column of water 10 m high; 10 m under water the pressure on a diver is 200 kPa. The volume of gas in an early diving bell full of air at sea level is halved at 10 m according to Boyle’s law; at 20 m pressure is 300 kPa absolute and the gas is compressed into one third the volume.

Dry air is composed of roughly 21% oxygen, 78% nitrogen, and 1% other gases. According to Dalton’s law the partial pressure of oxygen at any depth will be 21% of the total pressure exerted by the air and the partial pressure of nitrogen will be 78% of total pressure.

Gases dissolve in the liquid with which they are in contact. Nitrogen is fat soluble and at sea level we have several litres dissolved in our bodies. If the partial pressure of nitrogen is doubled (by breathing air at 10 m depth) for long enough for equilibration to take place we will contain twice as many dissolved nitrogen molecules as at sea level.

6 0
3 years ago
PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!
Mila [183]

Answer:

m\angle H = 44.4\°.

Step-by-step explanation:

Given:

In Right Angle Triangle GIH

∠ I = 90°

GI = 7    ....Side opposite to angle H

GH = 10  .... Hypotenuse

To Find:

m∠H = ?

Solution:

In Right Angle Triangle ABC ,Sine Identity,

sin \ H = \frac{Oppsite\  side\  to\  \angle H}{Hypotenuse}

Substituting the values we get;

sin\ H = \frac{7}{10} = 0.7

Now taking sin^{-1} we get;

\angle H = sin^{-1}\ 0.7 = 44.427

rounding to nearest tenth we get.

m\angle H = 44.4\°.

Hence m\angle H = 44.4\°.

6 0
3 years ago
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