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elena-s [515]
3 years ago
8

According to a report from the United States Environmental Protection Agency, burning one gallon of gasoline typically emits abo

ut 8.9 kg of CO2. A fuel company wants to test a new type of gasoline designed to have lower CO2 emissions. Here are their hypotheses:
H0: μ = 8.9 kg
Ha: μ < 8.9 kg (where μ is the mean amount of CO2 emitted by burning one gallon of this new gasoline).

Which of the following would be a Type II error in this setting?

A. The mean amount of CO2 emitted by the new fuel is actually 89 kg but they conclude it is lower than 89 kg
B. The mean amount of CO2 emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg
C. The mean amount of CO2 emitted by the new fuel is actual 89 kg and they alto conclude it is lower than 89 kg and they conclude it is lower than 9 kg
D. The mean amount of CO2 emitted by the new fuels actually lower than 8.9
Mathematics
1 answer:
Minchanka [31]3 years ago
8 0

Answer:

B. The mean amount of CO_2 emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg

Step-by-step explanation:

A Type II error is the failure to reject a false null hypothesis.

Given the null and alternate hypothesis of a fuel company which wants to test a new type of gasoline designed to have lower CO_2 emissions.:

H_0: \mu = 8.9 kg\\H_a: \mu < 8.9 kg \\\text{ (where \mu is the mean amount of CO_2 emitted by burning one gallon of this new gasoline)}

where \mu is the mean amount of CO_2 emitted by burning one gallon of this new gasoline.

If the null hypothesis is false, then:

H_a: \mu < 8.9 kg

A rejection of the alternate hypothesis above will be a Type II error.

Therefore:

The Type II error is: (B) The mean amount of CO_2  emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg.

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seropon [69]
Par value means that the stock is quoted at the face or principal value.

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Therefore, the answer is below par.



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7 0
3 years ago
Solve for r. Show your work!<br> 12 =R– (34 – 2)<br><br> Helpppp!!
amm1812

Answer:

r = 44

Step-by-step explanation:

12 = r - (34 - 2)

Solve for r

___________

To solve, we need to isolate r.

Distribute the negative sign with the numbers within the parenthesis :

12 = r - 34 + 2

Add like terms :

12 = r - 32

Add 32 to both sides :

44 = r

r = 44

4 0
3 years ago
Read 2 more answers
PLEASE HELP ME!!
Grace [21]
Take the derivative:
g’(x) = 12x^3 - 24x^2

Set equal to zero and solve:
0 = 12x^3 - 24x^2
0 = 12x^2 (x - 2)

x = 0 or x = 2

Plug back into original
g(0) = 3(0^4) - 8(0^3)
g(0) = 0 - 0
g(0) = 0

g(2) = 3(2^2) - 8(2^3)
g(2) = 3(4) - 8(8)
g(2) = 12 - 64
g(2) = -52

There is an absolute max at (0,0) or when x = 0
5 0
3 years ago
If someone could please help me I’m confused thanks:)
Sedbober [7]
<h3>Answer:  x = 45</h3>

Work Shown:

x+x+90 = 180 .... all three angles of a triangle add to 180

2x+90 = 180

2x = 180-90

2x = 90

x = 90/2

x = 45

This is a 45-45-90 right triangle. We also consider it an isosceles right triangle because the base angles (45) are equal.

3 0
3 years ago
What is the total weekly pay for a person earning $9.00 an hour and working only 8 hours a day for 5 days?
melomori [17]
First you woyld find how many hours total he worked.
5 \times 8 = 40
Then take the number of hours and multiply by the pay earned per hour.
40 \times 9 = 360
They would make $360 per week.
6 0
3 years ago
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