Answer:
she would run 6.4 miles in 48 min
Step-by-step explanation:
hope it helps
The answer is: 83 + 12√35
(a + b)² = a² + 2ab + b²
In (2√5 + 3√7)², a = 2√5, b = 3√7
Just substitute a and b:
(a + b)² = a² + 2ab + b² = (2√5)² + 2 * 2√5 * 3√7 + (3√7)² =
= 2²√5² + 2 * 2 * 3 * √5 * √7 + 3²√7² =
= 4 * 5 + 12 * √(5*7) + 9 * 7 =
= 20 + 12 *√35 + 63 =
= 83 + 12√35
Answer:
50√3 ≈ 86.6 m
Step-by-step explanation:
The geometry can be modeled by a right triangle with the height of the kite being the leg opposite the 60° angle. The hypotenuse has the given length of 100 m.
The mnemonic SOH CAH TOA reminds you that the relation between angles and the sides of interest here is ...
Sin = Opposite/Hypotenuse
sin(60°) = (kite height)/(100 m)
kite height = (100 m)·sin(60°) = (100 m)(√3)/2
kite height = 50√3 m ≈ 86.6 m
Label the 3 distinct sides of the box. I arbitrarily chose the letters a, b and c.
Use the info about areas as follows:
ab=54 in^2
ac=90 in^2
bc=60 in^2
Here you have 3 equations in 3 unknowns (a, b and c), which is enough info to use to determine a, b and c. Then the volume of the box is a*b*c.
Example: bc = 90, but c = 60/b. You could subst. 60/b for c in the 2nd and 3rd equation, which will eliminate c completely and leave you with 2 equations in 2 unknowns.
Continuing this procedure, I determined that a=9, b=6 and c=10. Thus, the volume of the box is V = 9*6*10 = 540 cubic inches (answer)
Answer:
c= -2 1/2
Step-by-step explanation:
