4 years ago

What is the volume of a cone that has a circumference of 309 feet and a height of 18 feet

Mathematics

2 answers:

Bas_tet [7]4 years ago

4 0

Answer:

v = 1.8 x 10^6

Step-by-step explanation:

v= π r 2h /3

kolezko [41]4 years ago

4 0

Answer:

V = 45,235 ft³

Step-by-step explanation:

The general formula for the volume of a cone:

V = $\frac{1}{3}$ πr³, where r = radius

Given the circumference of 309 feet, you can solve to find the radius of the cone:

C = 2πr or 309 = 2πr

Divide by 2π: 309/2π = 2πr/2π

Solve: r ≈ 49

V = $\frac{\pi r^{2}h}{3}=\frac{\pi 49^{2}}{3}=45,235$

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Read 2 more answers

Find all solutions to the equation in the interval [0,2pi). Enter the solutions in increasing order. Cos 2x = cos x

goblinko [34]

Step-by-step explanation:

$\cos(2x) = \cos(x)$

$\cos {}^{2} (x) - \sin {}^{2} (x) = \cos(x)$

$\cos {}^{2} (x) - (1 - \cos {}^{2} (x) ) = \cos(x)$

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$2 \cos {}^{2} (x) - \cos(x) - 1 = 0$

$2 \cos {}^{2} (x) - 2 \cos(x) + \cos(x) - 1 = 0$

$2 \cos(x) ( \cos(x) - 1) + 1( \cos(x) + 1)$

$(2 \cos(x) + 1)( \cos(x) - 1) = 0$

$2 \cos(x) + 1 = 0$

$2 \cos(x) = - 1$

$\cos(x) = - \frac{1}{2}$

$x = \frac{2\pi}{3} ,x = \frac{4\pi}{3}$

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$\cos(x) = 1$

$x = 0$

So our answer are

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2 years ago

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zimovet [89]

Answer:

Step-by-step explanation:

Let x= number of visits she makes

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9x+32<= 122

8 0

3 years ago