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3 years ago

The product of 6 and the sum of 3 times a number n and 5

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

5 0

Answer:

Step-by-step explanation:

6 (3n+5)

use the distributive property

18n+35

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Write an equation for a line parallel to y=3x-3 and passing through the point (4,15)

Andrews [41]

Hello!

To find the equation of a line parallel to y = 3x - 3 and passing through the point (4, 15), we need to know that if two lines are parallel, then their slopes are equivalent.

This means that we create a new equation in slope-intercept form, which includes the original slope, which is equal to 3.

In slope-intercept form, we need a y-intercept. So, we would substitute the given ordered pair into the new equation with the same slope and solve.

Remember that slope-intercept form is: y = mx + b, where m is the slope and b is the y-intercept.

y = 3x + b (substitute the ordered pair (4, 15))

15 = 3(4) + b (simplify)

15 = 12 + b (subtract 12 from both sides)

3 = b

Therefore, the equation for the line parallel to the line y = 3x - 3, and passing through the point (4, 15) is y = 3x + 3.

8 0

3 years ago

a 28 ft. ladder leaning against a vertical wall makes an angel of 80 degrees with the ground. How far from the base of the wall

worty [1.4K]

Answer:

The ladder is 4.86 foot from the base of the wall .

Step-by-step explanation:

Given as :

The length of the ladder = 28 ft

The ladder makes angle of 80° with the ground

Let The distance of the ladder from the foot of the wall = x ft

Now, From Triangle BAC

Cos angle = $\dfrac{\textrm Base}{\textrm Hypotenuse}$

I.e Cos 80° = $\dfrac{\textrm BA}{\textrm AC}$

Or, 0.1736 = $\dfrac{\textrm x}{\textrm 28}$

Or, x = 0.1736 × 28

∴ x = 4.86 foot

So, The distance of ladder from wall base = x = 4.86 foot

Hence The ladder is 4.86 foot from the base of the wall . Answer

3 0

2 years ago

Help please for these two

evablogger [386]

The measure of angle 2 is 129 degrees

4 0

1 year ago

NEED ANSWER ASPA.... PLS HURRY

a_sh-v [17]

We have that
$y=- x^{2} +36$

we know that
Is the equation of a vertical parabola open down
so
the vertex is a maximum

step 1
convert the equation of the parabola in the vertex form
$y=- x^{2} +36 \\ y-36=- x^{2}$

the vertex (h,k) is the point (0,36)

Part a) The point on the graph where the height of the tunnel is a maximum is (0,36)

Part b) The points on the graph where the height of the tunnel is zero feet is when y=0
so
for y=0
$- x^{2} +36=0 \\ x^{2} =36 \\ x= (+/-) 6$

the points are (-6,0) and (6,0)

see the attached figure