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Aleksandr [31]
3 years ago
15

What is (2.25*10 to the 4th exponent)+(5.4*10to the 5th exponent)

Mathematics
1 answer:
neonofarm [45]3 years ago
4 0

Answer:

8759345.0625

Step-by-step explanation:

22.5x22.5x22.5x22.5 = 256289.0625

54x54x54x54 = 8503056

256289.0625  + 8503056 = 8759345.0625


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Given the sequence, 26, 13, 6.5, ..... find a) the 10th term and b) the sum of the first 18 terms
Hunter-Best [27]

Answer:

a) 10th term is 0.051

b) The sum of first 18 terms of given sequence is 51.48

Step-by-step explanation:

We are given the sequence 26, 13, 6.5, ..... we need to find

a) 10th term

b) Sum of first 18 terms

Before solving we need to determine if the sequence is arithmetic or geometric

The sequence is arithmetic if common difference d is same.

The sequence is geometric if common ratio r is same.

Finding common difference d: 13-26 = -13, 6.5-13= -6.5

As common difference is not same so, the sequence is not arithmetic.

Finding common ratio r : 13/26 =0.5, 6.5/13= 0.5

As common ratio is same so, the sequence is geometric.

a) Finding common difference: 13-26 = -13, 6.5-13= -6.5

As common difference is not same so, the sequence is not arithmetic.

a) 10th term

The formula to find 10th term is: a_n=a_1r^{n-1}

We have a₁=26 and r = 0.5 n=10

a_n=a_1r^{n-1}\\a_{10}=26(0.5)^{10-1}\\a_{10}=26(0.5)^{9}\\a_{10}=0.051

So, 10th term is 0.051

b) Sum of first 18 terms

The formula to find sum of geometric series is: S_n=\frac{a(1-r^n)}{1-r}

where a= 1st term, r = common ratio and n= number of terms

In the given sequence we have

a=26, r=0.5 and n=18

Finding sum of first 18 terms

S_n=\frac{a(1-r^n)}{1-r}\\S_{18}=\frac{26(1-(0.5)^{18}}{1-0.5}\\S_{18}=\frac{26(0.99)}{0.5}\\S_{18}=\frac{25.74}{0.5}\\S_{18}=51.48

So, sum of first 18 terms of given sequence is 51.48

6 0
3 years ago
50 POINTS! PLEASE HELP!
Hunter-Best [27]

p would be the number of parking meters that dont accpet nickels and the p^ would be the number of parking meters that accpet nickels


8 0
3 years ago
Read 2 more answers
In a circle of radius 10 cm, a sector has an area of 40 (pi) sq. cm. What is the degree measure of the arc of the sector?
Rashid [163]

Answer:

144°

Step-by-step explanation:

First, find the area of the circle, with the formula A = \pir²

Plug in 10 as the radius, and solve

A = \pir²

A = \pi(10²)

A = 100\pi

Using this, create a proportion that relates the area of the sector to the degree measure of the arc.

Let x represent the degree measure of the arc of the sector:

\frac{40\pi }{100\pi } = \frac{x}{360}

Cross multiply and solve for x:

100\pix = 14400\pi

x = 144

So, the degree measure of the sector arc is 144°

6 0
3 years ago
Read 2 more answers
4x - 4y = -2<br> -9x - 4y = -3
liubo4ka [24]

Answer:

x=1/13 y=15/26

Step-by-step explanation:

hope this helps!

please mark me brainliest! thanks!

7 0
3 years ago
Drag the numbers below to put them in order from least to greatest:
sesenic [268]

Answer:

-0.5 , -0.85 , -0.87 , -0.9 , -0.9 , -1.2 , -1.67, -1.67

Step-by-step explanation:

you put the LEAST negative numbers frist, then you work your way up!

4 0
2 years ago
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