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yaroslaw [1]
3 years ago
8

Since opening night, attendance at play A has increased steadily, while attendance at play B first rose and then fell. Equations

modeling the daily attendance y at each play are shown below, Where x is the number of days since opening night. On what day(s) was the attendance the same at both plays? What was the attendance? Play A: y=16x+150 Play B: y=-x^2+60x-10 A. The attendance was the same on day 40. The attendance was 790 at both plays that day. B. The attendance was the same on day 4. The attendance was 214 at both plays that day. C. The attendance was the same on days 4 and 40. The attendance at both plays on those days was 214 and 790 respectively. D. The attedance was never the same at both plays.
Mathematics
2 answers:
SSSSS [86.1K]3 years ago
4 0

Answer:

4th day and the attendance was 214

Step-by-step explanation:


lina2011 [118]3 years ago
3 0
The two lines intersect at the point (4, 214). This means that the attendance was 214 for both plays on the 4th night. 

<span>B. The attendance was the same on day 4. The attendance was 214 at both plays that day.</span>
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Answer:

(A) There should have been 5 outcomes of HT

(B) The experimental probability is greater than the theoretical probability of HT.

Step-by-step explanation:

Given

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n(S) = 4 --- Sample Size

Solving (a); theoretical outcome of HT in 20 tosses

First, calculate the theoretical probability of HT

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<em></em>

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Step-by-step explanation:

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