Answer:
Laplace transforms turn a Differential equation into an algebraic, so we can solve easier.
y'= pY-y(0)
y"=p²Y - py(0)- y'(0)
Substituting these in differential equation :
p²Y -py (0) -y' (0)-6(pY-y(0)) + 13Y
Substituting in the initial conditions given , fact out Y, and get:
Y( p²-6p+13) = -3
Y=-3/ p²-6p+13
now looking this up in a table to Laplace transformation we get:
y=-3/2.e³т sin(2t)
for the last one, find the Laplace of t∧2 . which is 2/p³
pY - y(0)+ 5Y= 2/p³
Y= 2/p³(p+5)
Taking partial fractions:
Y=-2/125(p+5) + 2/125p - 2/25p² + 2/5p³
Learn more about differential equation here:
brainly.com/question/14620493
#SPJ4
$52,000 + 6% = $55,120
If this helped you, would you mind answering one of my recent questions? Thanks!
Answer:
The diameter of the model is 14.4 inches.
Step-by-step explanation:
The Diameter of the moon = 2,160 miles
The scale on the model represents 1 in = 150 miles
Let the model represents k inches in 2,160 miles.
So, by the Ratio of Proportionality:

⇒
or, k = 14.4 inches
⇒On the scale 2160 miles is represented as 14.4 inches
Hence the diameter of the model is 14.4 inches.
I would either round it to the 10th or 100th place.
Answer:
Its 72Pi. (Option C)
Step-by-step explanation:
Took it on Edge and got it right