Is it a yardstick? It has 2 ft of the edges and one ft in the middle.
So we need to find the common multiples of 6 and 12. Which are basically the multiples of 12, since 6 is always divisible to 12. So (12, 24, 36, 48, 60, 72, 84, 96, 108) Since it is a factor of 108, we stop at 108 (since a number greater than 108 can't be a factor of 108)
Now we find the factors of 108
108=<span>1,2,3,4,6,9,12,18,27,36,54,108
The numbers in both lists are 36 and 108 but since Micah is thinking of a 2-digit number, the number she is thinking of is 36.</span>
You need to complete the square in x and in y,

First, group the x-terms and the y-terms separately.

Move the 10 to the right side by subtracting 10 from both sides.

Now complete the square in x and in y.
The constant you need to add to complete each square is the square of half of the coefficient of the x or y term. Make sure to add the constants to both sides of the equation.

In the analysis of an infinite series, the sequence of partial sums are can be classified as either convergent of divergent. The series can be classified as a convergent sequence when a limit exists and is finite. The opposite is true, where the sequence of partial sums can be classified as a divergent sequence when the limit doesn't exist or is positive of negative infinity.