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Tju [1.3M]
2 years ago
11

PLEASE HELPP!!

Mathematics
1 answer:
Rasek [7]2 years ago
3 0

Answer:

Given:

Two trail maps:

Trail on the first map = 8 cm

Trail on the second map = 6 cm

Scale on first map = 1 cm : 2 km

A) What is the scale factor from the map to the actual trail?

For the first map, the scale factor is 1 cm: 2km. Therefore the actual trail is 8 centimeters * 2 kilometers = 16 km.

The scale factor of the second map is 16 km / 6 cm = 2.67 km : 1 cm

B) The length of the actual trail is 16 kilometers.

Step-by-step explanation:

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x + 1 = 3x + 6
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x - 5 = 3x
Subtract x from both sides
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Divide 2 from both sides
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6 0
2 years ago
1. The hypotenuse of a right triangle has a length of 10.0 and one of its
Mamont248 [21]

Answer:

I wont tell you the answer but I can tell you how to solve this one.

Step-by-step explanation:

If they are both squared then square them. Once you have the hypotenuse and the leg squared subtract the leg from the hypotenuse. That's your answer. Then you un- square it by finding the square root of the new number. That square root is your answer

7 0
2 years ago
A STUDENT FINISHES THEIR FISR HALF OF AN EXAM IN 2/3 THE TIME IT TAKES HIM TO FINISH THE SECOND HALF. IF THE ENTIRE EXAM TAKES H
shepuryov [24]

Answer: First half was 24 minutes

Step-by-step explanation:

Let the time taken to finish the second half be y.

Since the student used 2/3 of the second half time to finish the first half, first half = 2/3 × y = 2y/3

The entire exam is an hour which equals 60 minutes

First half + Second half = 60minutes

Note that first half is denoted as 2y/3 and second half is denoted by y.

2y/3 + y = 60

5y/3 = 60

Cross multiply

5y = 60 × 3

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Second half took 36 minutes

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8 0
3 years ago
Bryce tried to solve an equation step by step. \qquad\begin{aligned} \dfrac83&=3\left(c+\dfrac53\right)\\\\ \\ \dfrac83&
sesenic [268]

Answer:

Bryce is wrong in step 1 because he did not distribute 3 over 5/3

Explanation

Given the steps taken by bryce as shown, we are to find where he made an error

\qquad\begin{aligned} \dfrac83&=3\left(c+\dfrac53\right)\\\\ \\ \dfrac83&=3c+\dfrac53&\green{\text{Step } 1}\\\\ \\ 1&=3c&\blue{\text{Step } 2}\\\\ \\ \dfrac13&=c&\purple{\text{Step } 3}\\\\ \end{aligned}

Given the expression;

\dfrac83&=3\left(c+\dfrac53\right)\\\\ \\

Step 1:Expand the bracket using the distributive law;

8/3 = 3c + 3(5/3)

<em>Simplify</em>

8/3 = 3c + 15/3

Step 2: Subtract 15/3 from both sides

8/3 - 15/3 = 3c+15/3-15/3

(8-15)/3 = 3c

-7/3 = 3c

Step 3: Multiply both sides by 1/3

-7/3 * 1/3 = 3c * 1/3

-7/9 = c

Swap

c = -7/9

From the calculation, we can see that Bryce is wrong in step 1 because he did not distribute 3 over 5/3 thereby making his solution incorrect

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I got ECHA... hope it's right:)

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