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vlabodo [156]
3 years ago
12

Convert the mixed numbers to improper fractions:1. 5 6/72. 8 3/9

Mathematics
1 answer:
finlep [7]3 years ago
5 0
1. 5x72+6 over 72 = 366/72
2. 8x9+3 over 9. = 75/9
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Same question for this. Actually need help... ;-;​
Bess [88]
372 is the answer.
(9*6*3)+(10*7*3)=372
7 0
3 years ago
Given h(x) = 4x2 - 5x + 4 find h(-5).
MrRissso [65]

9514 1404 393

Answer:

  h(-5) = 129

Step-by-step explanation:

Put -5 where x is and do the arithmetic.

  h(-5) = 4(-5)² -5(-5) +4

  h(-5) = 4(25) +25 +4 = 129

7 0
3 years ago
Read 2 more answers
Which shows one way to determine the factors of x3 11x2 – 3x – 33 by grouping? x2(x 11) 3(x – 11) x2(x – 11) – 3(x – 11) x2(x 11
Aloiza [94]

The one way to determine factors of x³  + 11x² – 3x – 33  will be x^2(x+11)-3(x+11)_.

<h3>What is a factorization?</h3>

It is the method to separate the polynomial into parts and the parts will be in multiplication. And the value of the polynomial at this point will be zero.

The steps involved in the factorization are;

1. For each pair of parentheses, we create a common factor.

2. We use x2 as a common factor for the first parenthesis.

3. We use common factor 3 for the second parenthesis.

x^3  + 11x^2 - 3x -33 \\\\ x^2(x+11)-3(x+11)_

We will find the final solution as x^2(x+11)-3(x+11)_.

Hence the one way to determine factors of x³  + 11x² – 3x – 33  will be x^2(x+11)-3(x+11)_.

To learn more about the factorization refer to the link;

brainly.com/question/24182713

3 0
2 years ago
What is the base (in inches) of a triangle with an area of 161 square inches and a height of 14 inches?
pantera1 [17]

\textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh ~~ \begin{cases} b=base\\ h=height\\[-0.5em] \hrulefill\\ h=14\\ A=161 \end{cases}\implies 161=\cfrac{1}{2}b(14) \\\\\\ 161=7b\implies \cfrac{161}{7}=b\implies 23=b

7 0
2 years ago
To join a Yoga club there is a $100 annual fee and a $5 fee for each class you attend.
Leona [35]

Answer:

210

Step-by-step explanation: so 5 times 12 120 plus 100 is 210

5 0
3 years ago
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