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Snowcat [4.5K]
3 years ago
7

Ryan is trying to determine whether 2.7x – 5.9 is equivalent to 2.8x – 5.9. To test this, he substitutes 0 for x into both expre

ssions. Explain why this will not give him the correct answer.
Mathematics
2 answers:
torisob [31]3 years ago
7 0
Because 2.7*0 = 0  and 2.8*0 = 0

He needs to plug in some other value like x = 1
Bogdan [553]3 years ago
7 0
Each of the 2 expressions given is a linear function of the form y = mx + b.
These two fundtions have the same y-intercept:  -5.9, but the slopes of the two lines are different.  In both cases, f(0) = 0 - 5.9, but this does not indicate that 2.7x-5.9 = 2.8x-5.9 in general.

If Ryan were to subst. 1 for x in these two functions, the results would not be identical:  2.7(1) - 5.9 and 2.8(1) - 5.9.

Hope Ryan comes to realize that this test of his will not give him the correct answer.

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Find m∠IUV if m∠IUV=x+49, m∠TUI=x+63, and m∠TUV=106∘.?<br> I'll mark you brainliest!
8090 [49]

Answer:

46

Step-by-step explanation:

You have to do IVU+TUI=TUV

so... x+49+x+63=106

5 0
3 years ago
Be sure to answer all parts. List the evaluation points corresponding to the midpoint of each subinterval to three decimal place
gayaneshka [121]

Answer:

The Riemann Sum for \int\limits^5_4 {x^2+4} \, dx with n = 4 using midpoints is about 24.328125.

Step-by-step explanation:

We want to find the Riemann Sum for \int\limits^5_4 {x^2+4} \, dx with n = 4 using midpoints.

The Midpoint Sum uses the midpoints of a sub-interval:

\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f\left(\frac{x_0+x_1}{2}\right)+f\left(\frac{x_1+x_2}{2}\right)+f\left(\frac{x_2+x_3}{2}\right)+...+f\left(\frac{x_{n-2}+x_{n-1}}{2}\right)+f\left(\frac{x_{n-1}+x_{n}}{2}\right)\right)

where \Delta{x}=\frac{b-a}{n}

We know that a = 4, b = 5, n = 4.

Therefore, \Delta{x}=\frac{5-4}{4}=\frac{1}{4}

Divide the interval [4, 5] into n = 4 sub-intervals of length \Delta{x}=\frac{1}{4}

\left[4, \frac{17}{4}\right], \left[\frac{17}{4}, \frac{9}{2}\right], \left[\frac{9}{2}, \frac{19}{4}\right], \left[\frac{19}{4}, 5\right]

Now, we just evaluate the function at the midpoints:

f\left(\frac{x_{0}+x_{1}}{2}\right)=f\left(\frac{\left(4\right)+\left(\frac{17}{4}\right)}{2}\right)=f\left(\frac{33}{8}\right)=\frac{1345}{64}=21.015625

f\left(\frac{x_{1}+x_{2}}{2}\right)=f\left(\frac{\left(\frac{17}{4}\right)+\left(\frac{9}{2}\right)}{2}\right)=f\left(\frac{35}{8}\right)=\frac{1481}{64}=23.140625

f\left(\frac{x_{2}+x_{3}}{2}\right)=f\left(\frac{\left(\frac{9}{2}\right)+\left(\frac{19}{4}\right)}{2}\right)=f\left(\frac{37}{8}\right)=\frac{1625}{64}=25.390625

f\left(\frac{x_{3}+x_{4}}{2}\right)=f\left(\frac{\left(\frac{19}{4}\right)+\left(5\right)}{2}\right)=f\left(\frac{39}{8}\right)=\frac{1777}{64}=27.765625

Finally, use the Midpoint Sum formula

\frac{1}{4}(21.015625+23.140625+25.390625+27.765625)=24.328125

This is the sketch of the function and the approximating rectangles.

5 0
4 years ago
Find the value of unknown angles.<br>Х<br>50​
Gennadij [26K]

Answer:

x  = 70^o

Step-by-step explanation:

Given

See attachment for triangle

Required

Find x

To solve for x, we make use of:

x + 50^o + 60^o = 180^o --- angles in a triangle

x + 110^o = 180^o

Collect like terms

x  = 180^o-110^o

x  = 70^o

6 0
3 years ago
What is the domain of the function graphed below?
WITCHER [35]

From the graph, the domain of the function will be {x| x = −2,1}. Then the correct option is D.

<h3>What is an asymptote?</h3>

An asymptote is a line that constantly reaches a given curve but does not touch at an infinite distance.

From the graph, the domain of the function will be

The function is not defined for x = 2 and x = -1.

Then the domain will be

{x| x = −2,1}

Then the correct option is D.

More about the asymptote link is given below.

brainly.com/question/17767511

#SPJ1

5 0
2 years ago
The height of a kicked football can be represented by the polynomial –15t2 + 17t + 4, where t is the time in seconds. Find the f
lozanna [386]

Answer:

(−5t−1)(3t−4)

Step-by-step explanation:

Factor −15t2+17t+4

−15t2+17t+4

=(−5t−1)(3t−4)

6 0
3 years ago
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