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AysviL [449]
3 years ago
6

What is the cost of two chocolate chip cookies that cost 30 cents each and three peanut butter cookies that cost 25 cents each?

Mathematics
2 answers:
BartSMP [9]3 years ago
7 0

Answer:

2 x 30 = 60 cents

3 x 25 = 75 cents

60 + 75 = 135 cents or 1 dollar 35 cents

Hope this helps

Step-by-step explanation:

djverab [1.8K]3 years ago
5 0

Answer:

135 cents or $1.35

Step-by-step explanation:

30 x 2 = 60 cents for the choc

25 x 3 = 75 cents for the pb

60+75=135

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1 day= ____________ seconds <br> Please show the work!!
Nimfa-mama [501]

Answer:

86400 seconds

Step-by-step explanation:

The unit of measurement "day" (symbol d) is defined as 86,400 SI seconds.

8 0
3 years ago
Read 2 more answers
Connor jogs at a constant rate of 3.5 miles per hour. The table shows the distance traveled for different numbers of hours. Drag
allsm [11]

Answer:

1st and 3rd go in the 1st box

2nd and 4th go in the 2nd box

last one goes in the last box

Step-by-step explanation:

1,2,3,4,5 and time spent jogging go in independent quantity

3.5, 7, 10.5, 14, 17.5 and distance traveled go in dependent quantity

m=3.5h goes in neither

3 0
3 years ago
The isosceles triangle below has one angle measure as shown what is the measure of each of the other angles?
SSSSS [86.1K]
The answer would be 65°.
This is because 180° -50° equals 130°. And 130° divided by two equals 65°. The two remaining angles must be equal because it is an isosceles triangle.
8 0
3 years ago
Please see the image and help with this homework problem. thank you!
dimulka [17.4K]

we have the function

E=\sin \frac{\pi}{14}t

Part a

For t=7

substitute in the given function

\begin{gathered} E=\sin \frac{\pi}{14}7 \\ E=1 \end{gathered}

For t=14

\begin{gathered} E=\sin \frac{\pi}{14}14 \\ E=0 \end{gathered}

For t=21

\begin{gathered} E=\sin \frac{\pi}{14}21 \\ E=-1 \end{gathered}

For t=28

\begin{gathered} E=\sin \frac{\pi}{14}28 \\ E=0 \end{gathered}

For t=35

\begin{gathered} E=\sin \frac{\pi}{14}35 \\ E=1 \end{gathered}

Observation: The values of E varies from -1 to 1, including the zero

Part B

Remember that

The Period goes from one peak to the next

so

Period=2pi/B

B=pi/14

Period=(2pi)/(pi/14)=2pi*14/pi=28

<h2>the period is 28 days</h2>
6 0
1 year ago
How many integers between 10000 and 99999, inclusive, are divisible by 3 or<br> 5 or 7?
Yuki888 [10]

Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) = \dfrac{90000}{3}=30000

n( divisible by 5) = \dfrac{90000}{5}=18000

n( divisible by 7) = \dfrac{90000}{7}=12857.14

n( divisible by 3 and 5) = n(3∩5)=\dfrac{90000}{15}=6000

n( divisible by 5 and 7) = n(5∩7) = \dfrac{90000}{35}=2571.42

n( divisible by 3 and 7) = n(3∩7) = \dfrac{90000}{21}=4285.71

n( divisible by 3,5 and 7) = n(3∩5∩7) = \dfrac{90000}{105}=857.14

As we know the formula,

n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

=30000+18000+12857.14-6000-2571.42-4258.71+857.14\\\\=48884.15

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

5 0
3 years ago
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