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ser-zykov [4K]
3 years ago
8

Helen filled a one-gallon jug with water. Then she poured three 12-ounce glasses of water from the jug. How much water remained

in the jug after she filled the glasses?​
Mathematics
1 answer:
valkas [14]3 years ago
3 0

Answer: 92 ounces

Step-by-step explanation:

There are three 12 ounce glasses. That makes 36 ounces. There are 128 fluent ounces in a gallon. subtract 36 from 128 and you will get the answer

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Jackie loves to cook fried foods. She recorded the total amount of oil that she used each month in the table below.
SpyIntel [72]
Answer

She used 6/15 litres of oil in January

Explanation

We are given that, in January, she used 3/5 of the amount of oil she used in February.

We are also given that, she used 2/3 litres of oil in February.

Therefore, amount of oil used in January is:

3/5 • 2/3 = 6/15

She used 6/15 litres of oil in January
6 0
3 years ago
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10x+2y=10 in slope intercept form
faust18 [17]
 <span>Slope-intercept form is Y = MX + B. This is in standard form, AX + BY = C. You have to move the X to the other side of the equation and simplify it. </span>
<span>10x - 2y = 10 </span>
<span>- 10x - 10x Subtract 10x from both sides </span>
<span>- 2y = - 10x + 10 Now everything is in the right place, but it still needs to be simplified. </span>
<span>Divide each term by -2, in order to isolate the variable Y. </span>
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<span>The answer is: y = 5x - 5</span>
7 0
3 years ago
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Write in standard form <br><br><br>5.13 x 10₇<br><br>*please help me*
mafiozo [28]

In the standard form, the number 7 here should be an exponent not a sub text.

Answer: 5.13 x 10^(7).

Done!

4 0
3 years ago
What is the polynomial function of lowest degree with lead coefficient 1 and roots 1 and 1 + i? f(x) = x2 – 2x + 2 f(x) = x3 – x
konstantin123 [22]

Answer:

f(x)=x^{3}-3x^{2} +4x-2

Step-by-step explanation:

we know that

The <u><em>conjugate root theorem</em></u> states that if the complex number a + bi is a root of a polynomial P(x) in one variable with real coefficients, then the complex conjugate a - bi is also a root of that polynomial

In this problem we have that

The polynomial has roots 1 and (1+i)

so

by the conjugate root theorem

(1-i) is also a root of the polynomial

therefore

The lowest degree of the polynomial is 3

so

f(x)=a(x-1)(x-(1+i))(x-(1-i))

Remember that

The leading coefficient is 1

so

a=1

f(x)=(x-1)(x-(1+i))(x-(1-i))\\\\f(x)=(x-1)[x^{2} -(1-i)x-(1+i)x+(1-i^2)]\\\\f(x)=(x-1)[x^{2} -x+xi-x-xi+2]\\\\f(x)=(x-1)[x^{2} -2x+2]\\\\f(x)=x^{3}-2x^{2} +2x-x^{2} +2x-2\\\\f(x)=x^{3}-3x^{2} +4x-2

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3 years ago
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Can anyone message me and help me out with some algebra 1 questions?
stira [4]

Answer:

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