All categories

3 years ago

Help me with this the question is in the picture

Mathematics

1 answer:

nasty-shy [4]3 years ago

6 0

Answer:

28:12

Step-by-step explanation:

You multiply both sides by the same number to increase a ratio, the only one you can do this with is 28:12 by multiplying the original ratio by 4

You might be interested in

14 + 72 x 1/10 + 4 x 1/1000 =

Naily [24]

Answer:

21.204

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Given the expression below, which statement is true about the

artcher [175]

Answer:

your correct answer is 3 no first ,

3 0

3 years ago

Write in the slope-intercept form an equation of the line that passes through the given points.

cluponka [151]

Answer:

y=17/3x-26

Step-by-step explanation:

So what you need to do is find the slope and y-intercept. Then, you write it in y=mx+b form. m=slope, b=y-intercept. So in this case, 17/3 is the slope, and -26 is the y-intercept. Hope this helps :)

7 0

3 years ago

A refrigerator has a volume given by the trinomial y^3 + 5y^2 – 14y. What are the possible dimensions of the refrigerator? Use f

Serhud [2]

Y^3 + 5y^2 - 14y

first factor out a "y"

y(y^2 + 5y - 14)

y(y + 7)(y - 2)

The dimensions are then;
y
y + 7
y - 2

7 0

3 years ago

Find the area of the triangle with the given vertices. Use the fact that the area of the triangle having u and v as adjacent sid

Gnom [1K]

Answer:

The area of the triangle is $A=\sqrt{\frac{4027}{2}}$

Step-by-step explanation:

Using the fact that the area of the triangle having u and v as adjacent sides is given by

$A=\frac{1}{2}||{\bf u} \times {\bf v} ||$

We know that we want to take a cross product to compute the area of the triangle, but we need to be careful because it doesn't make sense if we take the cross product of points.

The first step is to build some vectors that describe this triangle.

According with the graph we can build the vectors:

${\bf AB}$ and ${\bf AC}$

The vector ${\bf AB}$ is the difference of point B minus point A

${\bf AB}=(5-3,5-5,0-9)=(2,0,-9)$

and the vector ${\bf AC}$ is the difference of point C minus point A

${\bf AC}=(-4-3,0-5,2-9)=(-7,-5,-7)$

Next we need to find the cross product of this vectors.

${\bf AB} \times {\bf AC}=\begin{pmatrix}2&0&-9\end{pmatrix}\times \begin{pmatrix}-7&-5&-7\end{pmatrix}$

This is the definition of cross product of two vectors in space:

Let ${\bf u} = u_1{\bf i}+u_2{\bf j}+u_3{\bf k}$ and ${\bf v} = v_1{\bf i}+v_2{\bf j}+v_3{\bf k}$ be vectors in space. The cross product of ${\bf u}$ and ${\bf v}$ is the vector

${\bf u} \times {\bf v}=(u_2v_3-u_3v_2){\bf i}-(u_1v_3-u_3v_1){\bf j}+(u_1v_2-u_2v_1){\bf k}$

Applying this definition we get

${\bf AB} \times {\bf AC}=\begin{pmatrix}2&0&-9\end{pmatrix}\times \begin{pmatrix}-7&-5&-7\end{pmatrix}$

$\begin{pmatrix}0\cdot \left(-7\right)-\left(-9\left(-5\right)\right)&-9\left(-7\right)-2\left(-7\right)&2\left(-5\right)-0\cdot \left(-7\right)\end{pmatrix}\\\\\begin{pmatrix}-45&77&-10\end{pmatrix}$

$||{\bf AB} \times {\bf AC}||=\sqrt{(-45)^2+(77)^2+(-10)^2} \\\\||{\bf AB} \times {\bf AC}||=\sqrt{2025+5929+100}\\\\||{\bf AB} \times {\bf AC}||=\sqrt{8054}$

The area of the triangle is

$A=\frac{1}{2}||{\bf AB} \times {\bf AC} ||=\frac{1}{2}\sqrt{8054}=\sqrt{\frac{4027}{2}}$

7 0

4 years ago