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2 years ago

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HELP MEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEe

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stellarik [79]2 years ago

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All proofs start as.

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The distance between the library and town hall is 735 ft the actual distance is 612 ft what is the percent error. Round your ans

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well, we know the actual distance is 612, however the estimate is 735, is off by 735 - 612 = 123.

now if we take 612 to be the 100%, what is 123 off of it in percentage?

$\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 612&100\\ 123&x \end{array}\implies \cfrac{612}{123}=\cfrac{100}{x}\implies \cfrac{204}{41}=\cfrac{100}{x}\implies 204x=4100 \\\\\\ x = \cfrac{4100}{204}\implies x = \cfrac{1025}{51}\implies x \approx 20.098$

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Write 9.1 as a mixed number and as an improper fraction.<br> Do not try to simplify your answers.

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