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3 years ago

5

The population is decreasing at a rate of 5% per year. If the population is 30,000 today, what will the population be in 12 year

s?

2 answers:

Dmitrij [34]3 years ago

7 0

Answer:

the population should be around 16,210

Step-by-step explanation:

use the exponetional equation y= 30,000(0.95)^12

Lera25 [3.4K]3 years ago

5 0

Answer:12,000

Step-by-step explanation:

.05*30,000=1,500

1,500*12=18,000

30,000-18,000=12,000

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Find two vectors in R2 with Euclidian Norm 1<br> whoseEuclidian inner product with (3,1) is zero.

alina1380 [7]

Answer:

$v_1=(\frac{1}{10},-\frac{3}{10})$

$v_2=(-\frac{1}{10},\frac{3}{10})$

Step-by-step explanation:

First we define two generic vectors in our $\mathbb{R}^2$ space:

$v_1 = (x_1,y_1)$
$v_2 = (x_2,y_2)$

By definition we know that Euclidean norm on an 2-dimensional Euclidean space $\mathbb{R}^2$ is:

$\left \| v \right \|= \sqrt{x^2+y^2}$

Also we know that the inner product in $\mathbb{R}^2$ space is defined as:

$v_1 \bullet v_2 = (x_1,y_1) \bullet(x_2,y_2)= x_1x_2+y_1y_2$

So as first condition we have that both two vectors have Euclidian Norm 1, that is:

$\left \| v_1 \right \|= \sqrt{x^2+y^2}=1$

and

$\left \| v_2 \right \|= \sqrt{x^2+y^2}=1$

As second condition we have that:

$v_1 \bullet (3,1) = (x_1,y_1) \bullet(3,1)= 3x_1+y_1=0$

$v_2 \bullet (3,1) = (x_2,y_2) \bullet(3,1)= 3x_2+y_2=0$

Which is the same:

$y_1=-3x_1\\y_2=-3x_2$

Replacing the second condition on the first condition we have:

$\sqrt{x_1^2+y_1^2}=1 \\\left | x_1^2+y_1^2 \right |=1 \\\left | x_1^2+(-3x_1)^2 \right |=1 \\\left | x_1^2+9x_1^2 \right |=1 \\\left | 10x_1^2 \right |=1 \\x_1^2= \frac{1}{10}$

Since $x_1^2= \frac{1}{10}$ we have two posible solutions, $x_1=\frac{1}{10}$ or $x_1=-\frac{1}{10}$ . If we choose $x_1=\frac{1}{10}$ , we can choose next the other solution for $x_2$ .

Remembering,

$y_1=-3x_1\\y_2=-3x_2$

The two vectors we are looking for are:

$v_1=(\frac{1}{10},-\frac{3}{10})\\v_2=(-\frac{1}{10},\frac{3}{10})$

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3 years ago

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How many millilteres are in 2 and a 1\2

andrew11 [14]

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Ten years ago. Phukan is 18 years younger than Namwan.Currently, the sum of their ages is 100 years. Find their current ages.

yawa3891 [41]

Step-by-step explanation:

phukan = x

Nanwan = y

let this be a simultaneous equation.

x - y = 18.... equation i

x + y = 100.... equation ii

subtract equation i from equation ii

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y = 59

substitute y = 59 in equation ii to get x

x + 59 = 100

x = 100- 59

x = 41

Nanwan = 59, Phukan = 41

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3 years ago

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