Answer:
As per the question, we need to convert product of sum into sum of product,
Given:
(A' +B+C')(A'+C'+D)(B'+D'),
At first, we will solve to parenthesis,
= (A'+C'+BD) (B'+D')
As per the Rule, (A+B)(A+C) = A+BC, In our case if we assume X = A'+C', then,
(A' +B+C')(A'+C'+D) = (A'+C'+B)(A'+C'+D) = (A'+C'+BD)
Now,
= (A'+C'+BD) (B'+D') = A'B' + A'D' + C'B' +C'D' +BDB' +BDD"
As we know that AA' = 0, it mean
=A'B'+A'D'+C'B'+C'D'+D*0+B0
=A'B'+A'D'+C'B'+C'D' as B * 0 and D*0 = 0
Finally, minimum sum of product boolean expression is
A''B'+A'D'+C'B'+C'D'
=
Well, since it is asking for an average, we have to add
78+89+87+96=
350... then we divide by 4
which would be 87.5 which IS greater than 80 :)
and less than 90 :)
Answer:
(-b-81)/6=a
Step-by-step explanation:
3b−2a-17 = 4a+4b+64
3b-4b-17-64=4a+2a
-b-81=6a
(-b-81)/6=a
F(x)=2+3sin(theta)
f'(x)=3cos(theta)
To find the slope you need the value of theta. The general formula is:
y-f(xo)=f'(xo)-(x-xo)
D i think because it’s talking about the angling
