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nataly862011 [7]
3 years ago
13

Find the sum of the geometric sequence –3, 15, –75, 375, … when there are 9 terms and select the correct answer below.

Mathematics
2 answers:
Lemur [1.5K]3 years ago
4 0

Answer:

Answer: A. -976563

Step-by-step explanation:

Sn=sum of the n terms of the geometric sequence.

a= the first term

r=the common ratio

n=numbers of terms.

Sn=a[(1-r^n)/(1-r)]

In this case:

a=-3

r=a₂/a₁=15/-3=-5

n=9

S₉=-3[(1-(-5)⁹) / (1-(-5))=

S₉=-3(1+1953125)/6)=

S₉=-3(1953126/6)=

S₉=-3(325521)

S₉=-976563

zavuch27 [327]3 years ago
3 0
Sn=sum of the n terms of the geometric sequence.
a= the first term
r=the common ratio
n=numbers of terms.

Sn=a[(1-r^n)/(1-r)]

In this case:
a=-3
r=a₂/a₁=15/-3=-5
n=9

S₉=-3[(1-(-5)⁹) / (1-(-5))=
S₉=-3(1+1953125)/6)=
S₉=-3(1953126/6)=
S₉=-3(325521)
S₉=-976563

Answer: A. -976563
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Answer:

Step-by-step explanation:

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