The question is an illustration of combination and there are 729 potential pass codes available
<h3>How to determine the number of potential pass codes?</h3>
The given parameters are
Symbols available = 9
Length of pass code = 3
From the question, we understand that a symbol may be entered any number of times.
This means that each of the 9 available symbols can be used three times
So, the number of potential pass codes is
Passcodes = 9 * 9 * 9
Evaluate the product
Passcodes = 729
Hence, there are 729 potential pass codes available
Read more about combination at:
brainly.com/question/11732255
#SPJ1
Answer: y=2/3x-5
Explanation: The first thing I do is look for the y-intercept which is where the line goes through the y-axis, for this equation it's -5; then the slope the point goes up one and goes right 1.5, then put it into whole numbers so I'll times them by 2 so the slope is 2/3
With those you can put it into slope-intercept form: y=2/3x-5
Answer:
0.2125 approximately 0.213
Step-by-step explanation:
6 divided by 5 is 0, u put ur point that is 0., then u add 0 to the 5 that makes it 50, 6 into 50 is 8 remaining 3 u add it to the 0. making it 0.8 then u add 0 to the 3 making it 30, 6 into 30 answer is 5. So u divide 0.85 divided by 4which is equal to 0.2125 approximately that is when u round up the last number when it is up to 5 which it is, it is equal to 0.213. I hope this is helpful for you
