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telo118 [61]
3 years ago
14

Please stop and help me

Mathematics
1 answer:
Vladimir79 [104]3 years ago
4 0

Answer:

f(9)= 141

Step-by-step explanation:

f(x)=-x^{2}+5x+15

  • replace x's with 9
  • f(9)=-9^2+5(9)+15
  • solve
  • f(9)=141
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Which is equal to log base 2n=4
o-na [289]
To solve this problem you must apply the proccedure shown below:

 1. You have the following logarithm:

 <span>log(2)n=4

 2. Therefore, you con rewrite it as below:

 loga(b)=logb/loa
</span>
 3. Therefore, you have:

 log(2)n=4⇒log(n)/log(2)=4
 
 4. Then, you obtain:

 log(n)=4log(2)

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4 0
3 years ago
Read 2 more answers
Help help help help me pleaseeeeeeeee
kobusy [5.1K]

The ticket price which will maximize the student's council is: C. $3.10.

<h3>What is price?</h3>

Price can be defined as an amount of money which is primarily set by the seller of a product, and it must be paid by a buyer to the seller, so as to enable the acquisition of this product.

Based on the information provided about Valley High School student council, we can logically deduce the following data:

  • Total number of students = 420 students.
  • Lowest ticket price = $2.00.
  • Increase in ticket price = $0.20.
  • Attendance = 20 fewer students

<h3>How to determine the ticket price?</h3>

Mathematically, the equation which model the profit is given by:

Profit = price × number of tickets sold

P(x) = (2 + 0.2x)(420 - 20x)

P(x) = 840 + 84x - 40x - 4x²

P(x) = -4x² + 44x + 840.

For any quadratic equation with a parabolic curve, the axis of symmetry is given by:

Xmax = -b/2a

Xmax = -44/2(-4)

Xmax = -44/-8.

Xmax = 5.5

Ticket price for maximum profit is given by:

Ticket price = 2 + 0.2x

Ticket price = 2 + 0.2(5.5)

Ticket price = $3.10.

Read more on maximized profit here: brainly.com/question/13800671

#SPJ1

8 0
2 years ago
9. The ticket at right has a perimeter of 42 cm.
Liula [17]

Perimeter simply represents the sum of all side lengths of a shape. The length of the missing side of the ticket is 5 cm; the length of gold line on each ticket is 20 cm, and 2 bottles of gold ink are required to draw gold lines on 200 tickets.

I've added the image of the ticket as an attachment.

(a) The missing side length

From the attachment, the 4 unknown side lengths are equal. Represent this side length with L.

So, we have:

Perimeter =2\times 11 + 4 \times L

This gives

2\times11 + 4 \times L = 42

22 + 4 \times L = 42

Collect like terms

4 \times L = 42-22

4 \times L = 20

Divide both sides by 4

L =5cm

(b) The length of the gold lines

There are 4 slant lines and the length of one of the slant lines is 5 cm (as calculated above).

So, the length of the gold line is:

Gold = 4 \times L

Gold = 4 \times 5cm

Gold = 20cm

(c) The number of gold ink bottles.

n = 200 --- number of tickets

The length of all gold line in the 200 tickets is:

Length = 200 \times Gold

Length = 200 \times 20cm

Length = 4000 cm

Length = 4000 \times 0.01m ---- convert to meters

Length = 40m

Given that:

Bottle = 20m --- 1 bottle for 20 m

The number of bottles (n) is:

n = \frac{Length}{Bottles}

n = \frac{40m}{20m}

n = 2

Hence, 2 bottles of gold ink are enough.

Read more about perimeters at:

brainly.com/question/6465134

4 0
3 years ago
What are the solutions of -1 &lt;=x-3&lt;4? help asap ​
viva [34]
I think the answer is -1=x-3<4
4 0
2 years ago
Help me with the answer please
Dvinal [7]

Answer: your dumb

Step-by-step explanation:

7 0
3 years ago
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