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3 years ago

Requiem needs to know if the triangle shown is a right triangle. Which equation could he use to help ?

Mathematics

1 answer:

finlep [7]3 years ago

3 0

Answer:

Pythagoras theorem: hypotenuse² = opposite² + adjacent²

Step-by-step explanation:

To know if a triangle is a right angle, we need to have the length of each sides of the triangle. Then we would apply Pythagoras theorem to determine if it is truly a right angled triangle.

Pythagoras theorem is a theorem in the form of an equation which shows the relationship between the sides of a right angled triangle.

let the sides of the right angled triangle be:

opposite =a, adjacent = b and hypotenuse = c

Using Pythagoras theorem

hypotenuse² = opposite² + adjacent²

c² = a² + b²

If the left hand side of the equation = the right hand side of the equation, it is a right angled triangle.

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Nitella [24]

Answer:

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Step-by-step explanation:

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3 years ago

In Mr. Jegou's neighborhood 35% of the houses are blue. Write the

ivann1987 [24]

Answer:

Fraction: 3/20

Decimal: 0.35

Step-by-step explanation:

a) 100% - 35% = 65

So, 65% of the houses are NOT blue.

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Fraction: 3/20

Decimal: 0.35

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3 years ago

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Svetlanka [38]

Answer:

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Step-by-step explanation:

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3 years ago

If 5(x + 7)= -3, then 5x +35= -3

tensa zangetsu [6.8K]

= 5x + 35 = -3
- 35 = -35
5x = -38
/ 5 = / 5
x = -7.6

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3 years ago

Prove divisibility 45^45·15^15 by 75^30

Anuta_ua [19.1K]

Answer:

$3^{75}$

Step-by-step explanation:

We are asked to divide our given fraction: $\frac{45^{45}*15^{15}}{75^{30}}$ .

We will simplify our division problem using rules of exponents.

Using product rule of exponents $(a*b)^n=a^n*b^n$ we can write:

$45^{45}=(3*15)^{45}=3^{45}*15^{45}$

$75^{30}=(5*15)^{30}=5^{30}*15^{30}$

Substituting these values in our division problem we will get,

$\frac{3^{45}*15^{45}*15^{15}}{5^{30}*15^{30}}$

Using power rule of exponents $a^m*a^n=a^{m+n}$ we will get,

$\frac{3^{45}*15^{45+15}}{5^{30}*15^{30}}$

$\frac{3^{45}*15^{60}}{5^{30}*15^{30}}$

Using quotient rule of exponent $\frac{a^m}{a^n}=a^{m-n}$ we will get,

$\frac{3^{45}*15^{60-30}}{5^{30}}$

$\frac{3^{45}*15^{30}}{5^{30}}$

Using product rule of exponents $(a*b)^n=a^n*b^n$ we will get,

$\frac{3^{45}*(3*5)^{30}}{5^{30}}$

$\frac{3^{45}*3^{30}*5^{30}}{5^{30}}$

Upon canceling out $5^{30}$ we will get,

$3^{45}*3^{30}$

Using power rule of exponents $a^m*a^n=a^{m+n}$ we will get,

$3^{45+30}$

$3^{75}$

Therefore, our resulting quotient will be $3^{75}$ .

8 0

3 years ago