Let width and length be x and y respectively.
Perimeter (32in) =2x+2y=> 16=x+y => y=16-x
Area, A = xy = x(16-x) = 16x-x^2
The function to maximize is area: A=16 x-x^2
For maximum area, the first derivative of A =0 => A'=16-2x =0
Solving for x: 16-2x=0 =>2x=16 => x=8 in
And therefore, y=16-8 = 8 in
The polynomial for the perimeter starts from the formula for the perimeter of a rectangle as written below:
Perimeter = 2L + 2W = 2( L + W)
Perimeter = 2(4A + 3B + 3A - 2B)
Perimeter = 2(7A - B)
Let perimeter be P,
P = 14A - 2B --> this would be the polynomial
Let's substitute A=12 to the polynomial:
P = 14(12) - 2B = 168 - 2B
To determine the minimum P, set it to 0.0001.
0.0001 = 168 - 2B
B = 83.999 or 84
Thus, the minimum perimeter is achieved if the value of B approached to 84.
I think you have to solve like each section like (5x3+3)2 first solve that and then solve the middle one and then the last one and I think they all have to be equal to each other , and if they aren’t then her anwser isn’t correct
Answer:
5)
1
Expand by distributing terms.
-2x-2\times 5−2x−2×5
2
Simplify 2\times 52×5 to 1010.
-2x-10−2x−10
