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3 years ago

Which of the following graphs are identical? DONE.

Mathematics

2 answers:

Westkost [7]3 years ago

6 0

Answer:

I think it's the 1st and 3rd

Step-by-step explanation:

with square root and squaring, being positive/negative doesn't effect the answer. you can use a calculator if u want.

square root of 3 = square root of -3

square root of X = square root of -X

White raven [17]3 years ago

4 0

The fourth and sixth

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After x+1/3-x+2/2x have been combined using the least common denominator of 6x, what is the numerator

Harlamova29_29 [7]

The answer is: <span>(2x² + 2x)/(5x - 2)

</span>

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4 years ago

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Leo has had test scores of 85, 92 and 87. He has one test left. What test score t must he to average at least a 90 for his four

LenKa [72]

96

The mean of 85+92+87+96=90

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3 years ago

Quick i need help! (includeing pic)

allsm [11]

I believe the answer would be D :)

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3 years ago

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Im giving 100 Points to anyone who could solve this for me please.

myrzilka [38]

Answer:

AB = 27.2

BC = 33.5

AC = 50.4

∠A = 38°

∠ABC = 112°

Step-by-step explanation:

<u>Trigonometric ratios</u>

$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

$\implies \sf \cos(30^{\circ})=\dfrac{29}{BC}$

$\implies \sf BC=\dfrac{29}{\cos(30^{\circ})}$

$\implies \sf BC=\dfrac{58\sqrt{3}}{3}=33.5\:(nearest\:tenth)$

$\implies \sf \tan(30^{\circ})=\dfrac{BD}{29}$

$\implies \sf BD=29\tan(30^{\circ})$

$\implies \sf BD=\dfrac{29\sqrt{3}}{3}$

$\implies \sf \sin(38^{\circ})=\dfrac{BD}{AB}$

$\implies \sf AB=\dfrac{\dfrac{29\sqrt{3}}{3}}{\sin(38^{\circ})}$

$\implies \sf AB=27.2\:(nearest\:tenth)$

$\implies \sf \tan(38^{\circ})=\dfrac{BD}{AD}$

$\implies \sf AD=\dfrac{\dfrac{29\sqrt{3}}{3}}{\tan(38^{\circ})}$

$\implies \sf AD=21.4\:(nearest\:tenth)$

$\implies \sf AC=AD+DC=21.4+29=50.4$

The interior angles of a triangle sum to 180°

⇒ ∠A + 52° + 90° = 180°

⇒ ∠A = 180° - 90° - 52°

⇒ ∠A = 38°

⇒ ∠ABC + 38° + 30° = 180°

⇒ ∠ABC = 180° - 38° - 30°

⇒ ∠ABC = 112°

**I have checked the measures using a graphing programme - see attached**

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2 years ago

Henry says that his set of numbers includes all integers. Iliana argues that he is wrong.

Oduvanchick [21]

Answer:

Iliana is correct because Henry included a fraction. Fractions are not integers.

8 0

3 years ago