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melomori [17]
3 years ago
11

Penelope earned $50 in May. She earned $60 in June.

Mathematics
1 answer:
eduard3 years ago
7 0

Answer:

120% increase

Step-by-step explanation:

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6th grade math guys!! (:
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Answer:

it is at sea level because 0 meters above sea level indicates that it has not changed from sea level

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Helena had a balance of $14.48 left on a gift card. She bought a muffin each for her, and five of her friends. The cost of each
Ivenika [448]
She spent $6.12 on the muffins for her and her friends, and she has $8.36 left on her gift card. By multiplying 6 by $1.02, you get the amount she spent, and by subtracting $14.48 by $6.12, I find how much she has left on her gift card.
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Find the following: F(x, y, z) = e^(xy) sin z j + y tan^−1(x/z)k Exercise Find the curl and the divergence of the vector field.
natulia [17]

\vec F(x,y,z)=e^{xy}\sin z\,\vec\jmath+y\tan^{-1}\dfrac xz\,\vec k

Divergence is easier to compute:

\mathrm{div}\vec F=\dfrac{\partial(e^{xy}\sin z)}{\partial y}+\dfrac{\partial\left(y\tan^{-1}\frac xz\right)}{\partial z}

\mathrm{div}\vec F=xe^{xy}\sin z-\dfrac{xy}{x^2+z^2}

Curl is a bit more tedious. Denote by D_t the differential operator, namely the derivative with respect to the variable t. Then

\mathrm{curl}\vec F=\begin{vmatrix}\vec\imath&\vec\jmath&\vec k\\D_x&D_y&D_z\\0&e^{xy}\sin z&y\tan^{-1}\frac xz\end{vmatrix}

\mathrm{curl}\vec F=\left(D_y\left[y\tan^{-1}\dfrac xz\right]-D_z\left[e^{xy}\sin z\right]\right)\,\vec\imath-D_x\left[y\tan^{-1}\dfrac xz\right]\,\vec\jmath+D_x\left[e^{xy}\sin z}\right]\,\vec k

\mathrm{curl}\vec F=\left(\tan^{-1}\dfrac xz-e^{xy}\cos z\right)\,\vec\imath-\dfrac{yz}{x^2+z^2}\,\vec\jmath+ye^{xy}\sin z\,\vec k

5 0
3 years ago
A color printer prints 34 pages in 12 minutes. How many pages does it print per minutes?
RSB [31]

Answer:

almost 3 per minute but not just about there yet

Step-by-step explanation:

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6 0
3 years ago
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Gary learned that the value of his car depreciates by 15% percent per year. Which of the following functions best describes the
Sever21 [200]
For this case we have that the original value of the car is:
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 For the following year we have the value is:
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B.f (m) = 0.85m
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