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3 years ago

7

100 POINTS!!!!! Help Please I am begging you!

1 answer:

trapecia [35]3 years ago

4 0

Answer: The function is decreasing on the intervals (-∞,-2]U(-1,∞)

Step-by-step explanation:

You can see on the graph that the first part of the function is downward sloping from negative infinity until it's local minimum at (-2,1), and then goes up until the point (-1,2), where it drops to a new line segment that starts with a hole. I used parentheses for negative and positive infinity, as they are not defined numbers and thus cannot be exact. I also used parentheses for -1 has the part at -1 where it is decreasing is a hole, and is thus not actually decreasing at -1 but everywhere after -1.

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3 years ago

3. Which polynomial is equal to

Nataly_w [17]

Which polynomial is equal to (-3x^2 + 2x - 3) subtracted from (x^3 - x^2 + 3x)?

<h3><u><em>Answer:</em></u></h3>

The polynomial equal to (-3x^2 + 2x - 3) subtracted from (x^3 - x^2 + 3x) is $x^3 + 2x^2 + x + 3$

<h3><u><em>Solution:</em></u></h3>

Given that two polynomials are: $(-3x^2 + 2x - 3)$ and $(x^3 - x^2 + 3x)$

We have to find the result when $(-3x^2 + 2x - 3)$ is subtracted from $(x^3 - x^2 + 3x)$

In basic arithmetic operations,

when "a" is subtracted from "b" , the result is b - a

Similarly,

When $(-3x^2 + 2x - 3)$ is subtracted from $(x^3 - x^2 + 3x)$ , the result is:

$\rightarrow (x^3 - x^2 + 3x) - (-3x^2 + 2x - 3)$

Let us solve the above expression

<em><u>There are two simple rules to remember: </u></em>

When you multiply a negative number by a positive number then the product is always negative.

When you multiply two negative numbers or two positive numbers then the product is always positive.

So the above expression becomes:

$\rightarrow (x^3 - x^2 + 3x) + 3x^2 -2x + 3$

Removing the brackets we get,

$\rightarrow x^3 - x^2 + 3x + 3x^2 -2x + 3$

Combining the like terms,

$\rightarrow x^3 -x^2 + 3x^2 + 3x - 2x + 3$

$\rightarrow x^3 + 2x^2 + x + 3$

Thus the resulting polynomial is found

5 0

3 years ago