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zhenek [66]
4 years ago
15

If two parallel lines are cut by a transversal so the alternate interior angles are (congruent, supplementary, complementary), t

hen the lines are parallel.
Mathematics
2 answers:
Goryan [66]4 years ago
7 0

Answer:

if two parallel lines are cut by a transversal so that the alternate interior angles are <u>congruent,</u> then the lines are parallel.


OLEGan [10]4 years ago
5 0
If two parallel lines are cut by a transversal so that the alternate interior angles are congruent then the lines are parallel
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Find cos(β) in the triangle.
svetlana [45]

90°+b+b =180

90°+ 2b=180

2b=180-90

2b= 90

<u>2</u><u>b</u><u>=</u><u>9</u><u>0</u>

<u>2</u> = 2

b=45°

ave tried I don't know if its correct

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2 years ago
Solve the equation. 3p – 1 = 5(p – 1) – 2(7 – 2p) 3 -9 -10 0
Sati [7]

Answer:


Step-by-step explanation:

3p – 1 = 5(p – 1) – 2(7 – 2p) 3 -9 -10  First Distribute

3p-1= 5p-5-42+12p-9-10  Simplify all like factors

3p-1=17p-66 Add 66 on both sides

3p+65=17p Subtract 3p from both sides

65=15p Divide both sides by 15

p=4.3

if it is a 100

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3p-1=17p-156 Add 156 on both sides

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3 0
4 years ago
If there is 5.2% sales tax on a pair of jeans? How much is the total tax?
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How much is a pair of jeans? I can not answer the question if I do not know the price of the jeans.

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3 years ago
Read 2 more answers
find the surface area of a right regular hexagonal pyramid with sides 3 cm and slant heights 6cm. show all of your work.​
DedPeter [7]

Answer:

The surface area of right regular hexagonal pyramid = 82.222 cm³

Step-by-step explanation:

Given as , for regular hexagonal pyramid :

The of base side = 3 cm

The slant heights = 6 cm

Now ,

The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}

Where a is the base side

And h is the slant height

So, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}

Or, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 9 + 9 \sqrt{36+ 3\times \frac{9}{4}}

Or,  The surface area of right regular hexagonal pyramid = 23.38 + 9 × \frac{171}{4}

∴  The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538

I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842

So,  The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer

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Lynette's mother gives her $80. Lynette spends $5 per day. Lynette has y dollars left after x days.
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Lynette has $16 left after 75 days. I hope I'm right. 
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