Answer:
your answers will be 3 and 6
Step-by-step explanation:
have a nice day !!^_^
The probability of the arrow will land on a section labeled with the number greater than 3 is 
Step-by-step explanation:
Given,
The spinner is divided into 8 sections say named 1, 2, 3, 4, 5, 6, 7, 8
To find the P : probability of the arrow will land on a section labeled with the number greater than 3
Formula
<u>P = (the number of possible outcomes) ÷ ( the number of total result)</u>
We will count the probability when the arrow land on either 4 or 5 or 6 or 7 or 8 = 5 times
Total number of result = 8
Hence the probability = 
Answer:
1 ft. by 1 ft. by 1 ft.
1 mm by 1 mm by 1 mm
Step-by-step explanation:
it's a cube, all sides are the same :)
First, let's write it like this:

Subtract

from both sides.


Divide both sides by 3.


Now that we know what's the value of

, let's find the value of


Let's take the first part.

Multiply the fractions.

Cancel the common factor, which is 3.

We would be left with.

Add like terms.

We would be left with.

Subtract 8 from both sides.


This tells us that

can be any number.
Let me know if you need any help!
Thanks!
-TetraFish
Answer:
- radius: 1.84 in
- height: 3.68 in
Step-by-step explanation:
After you've worked a couple of "optimum cylinder" problems, you find that the cylinder with the least surface area for a given volume has a height that is equal to its diameter. So, the volume equation becomes ...
V = πr²·h = 2πr³ = 39 in³
Then the radius is ...
r = ∛(39/(2π)) in ≈ 1.83779 in ≈ 1.84 in
h = 2r = 3.67557 in ≈ 3.68 in
_____
The total surface area of a cylinder is ...
S = 2πr² + 2πrh
For a given volume, V, this becomes ...
S = 2π(r² +r·(V/(πr²))) = 2πr² +2V/r
The derivative of this with respect to r is ...
S' = 4πr -2V/r²
Setting this to zero and multiplying by r²/2 gives ...
0 = 2πr³ -V
r = ∛(V/(2π)) . . . . . . . . looks a lot like the expression above for r
__
If we substitute the equation for V into the equation just above this last one, we have ...
0 = 2πr³ - πr²·h
Dividing by πr² gives ...
0 = 2r - h
h = 2r . . . . . generic solution for cylinder optimization problems