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disa [49]
4 years ago
11

Guys help me with C D E

Mathematics
1 answer:
Aleks [24]4 years ago
5 0
C=N
D=B
E=M

Anyone feel free to correct me if you think I'm wrong (also needed more than 20 characters)
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Simplified form of 4(12x+16)
Ierofanga [76]

Answer:

The given expression simplified is <em>48x + 64.</em>

Step-by-step explanation:

Solving this problem entails of simplifying the expression provided. We'll use the distributive law, or the distributive property, to write the expression in the simplest form.

Distributive law states:

  • a(b + c) ⟶ (a × b) + (a × c)

We know that...

  • a = 4
  • b = 12x
  • c = 16

Following the rules of distributive law, we can set up the expression to match this property.

a(b + c)  ⟶  4(12x + 16)  ⟶  (4 × 12x) + (4 × 16)

The expression will now be easier to simplify. Here, the last step would be to multiply the terms within the parentheses. Remember that we <u>cannot</u> multiply a number by a variable. When you multiply '4' by '12x', just multiply twelve and four, and leave the variable as is.

(4 × 12x) + (4 × 16)

48x + (4 × 16)

48x + 64

Think back on what I mentioned earlier about not being able to multiply a number by a variable. The same rule applies to adding two terms, in which one is a constant and the other consists of a coefficient <u>and variable</u>. Our simplified expression has '48x', which is a coefficient and variable, and '64', which is a constant. This means we cannot add these two terms together.

Our expression seems to be in the simplest form because no further actions can be taken. The correct answer should be <em>48x + 64.</em>

6 0
3 years ago
3^4 + 2 ⋅ 5 = ____. (Input only whole numbers.)
meriva
91



Follow the order of operations.

3^4 + 2 * 5

81 + 2 * 5 (Exponent)

81 + 10 (Multiplication)

91 (Addition)



Please consider marking this answer as Brainliest to help me advance.
5 0
3 years ago
Integrate xe^(-x^2).
Gekata [30.6K]
You can easily integrate it using a simple substitution:

\large\begin{array}{l} \mathsf{\displaystyle\int\!x\,e^{-x^2}\,dx}\\\\ =\mathsf{\displaystyle\int\!\left(-\frac{1}{2}\right)\cdot (-2)x\,e^{-x^2}\,dx}\\\\ =\mathsf{\displaystyle-\,\frac{1}{2}\int\!\,e^{-x^2}\cdot (-2x)\,dx\qquad\quad(i)}\\\\ \end{array}


\large\begin{array}{l} \textsf{Let}\\\\ \mathsf{-x^2=u,}\quad\textsf{then}\quad\mathsf{-2x\,dx=du}\\\\\\ \textsf{so (i) becomes}\\\\ =\mathsf{\displaystyle-\,\frac{1}{2}\int\!e^u\,du}\\\\ =\mathsf{\displaystyle-\,\frac{1}{2}\cdot e^u+C}\\\\ =\mathsf{\displaystyle-\,\frac{1}{2}\cdot e^{-2x}+C}\\\\\\ \boxed{\begin{array}{c} \mathsf{\displaystyle\int\!x\,e^{-x^2}\,dx=-\,\frac{1}{2}\,e^{-x^2}+C} \end{array}}\qquad\checkmark \end{array}


If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2159730


\large\textsf{I hope it helps. :-)}


Tags: <em>integrate substitution indefinite integral exponential composite calculus</em>

7 0
4 years ago
Find the distance between the points A(13,2) and B(7,10)
Anna007 [38]

Answer:

10 = D

Step-by-step explanation:

Method #1

We can draw a <em>right triangle</em> on the graph upon where the points are located and use the Pythagorean Theorem:

{a}^{2} + {b}^{2} = {c}^{2}

{6}^{2} + {8}^{2} = {c}^{2}

36 + 64 = {c}^{2}

100 = {c}^{2}

10 = c

* Whenever we talk about distance, we ONLY want the NON-NEGATIVE root.

_______________________________________________

Method #2

Or, we can use the Distance Formula:

\sqrt{[-x_1 + x_2]^{2} + [-y_1 + y_2]^{2}} = D

<em>B</em>[7, 10] <em>A</em>[13, 2]

\sqrt{[-2 + 10]^{2} + [-13 + 7]^{2}} = D

\sqrt{8^{2} + [-6]^{2}} = D

\sqrt{64 + 36} = D

\sqrt{100} = D

10 = D

* Whenever we talk about distance, we ONLY want the NON-NEGATIVE root.

** You see? It does not matter which method you choose, as long as you are doing the work correctly.

I am delighted to assist you anytime.

6 0
3 years ago
Dave ran 10km in 40 minutes. He rested for 5 minutes then ran a further 8 km in 35 minutes.Work out his average speed for the wh
Nadya [2.5K]

Answer:

27/2 km/hr

Step-by-step explanation:

5 0
3 years ago
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