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Dvinal [7]
2 years ago
7

Help me please and thank you !

Mathematics
2 answers:
serg [7]2 years ago
7 0
The answer is C. Why? Well, see below!

A would be incorrect because the problem is asking what the area of the stamp would be. In order to find area, we multiply length and width by each other. The given equation we initially had shows division, and would therefore be incorrect. B would be incorrect because although the equation has the correct evaluation symbol, the formula for identifying length would be L = A / W, which means length equals area divided by width. Because the area is 1/4 in this problem, the expression used for evaluation would be 1/4 divided by 1/5. D is incorrect because, like B, the evaluation expression would be 1/4 divided by 1/5.

Your final answer: Because C is the only problem that gives us a corresponding expression to the initial expression, C is the correct answer. If you need extra help, let me know and I will gladly assist you.
olya-2409 [2.1K]2 years ago
6 0

Answer:

Step-by-step explanation:

(A)length of a stamp=1/5foot

wide of a stamp=1/4foot

area of the stamp=?

area of the stamp=length of a stamp *wide of a stamp

                              =1/5*1/4

                              =1/20square foot

(B)an area of the room=1/4  square meter

width of the room=1/5meter

length of the room=?

an area of the room=width of the room*length of the room

1/4                              =1/5                          *  length of the room

1/4                              = length of the room/5                

5/4                             =length of the room

<h3>length of the room   =5/4=1 1/4</h3>

(C)the area of the canvas=1/5square yard

width of the canvas=1/4 yard

length of the canvas=?

an area of the  canvas=width of the  canvas*length of the  canvas

1/5                                = width of the  canvas*1/4

1/5                                 = width of the  canvas/4

4/5                                =width of the  canvas

width of the  canvas=   4/5

(D)length of the  rectangular course=1/5mile

area of the  rectangular course=1/4square mile

width of the  rectangular course=?

an area of the  rectangular course

                          =

width of the  rectangular course*length of the  rectangular course

1/4                      =width of the  rectangular course*1/5

1/4                      =width of the  rectangular course/5

5/4                     =width of the  rectangular course

width of the  rectangular course=5/4

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Step-by-step explanation:

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3 years ago
Can someone help me with this? Please this would mean so much.
Paha777 [63]

Answers:

x = angle MLN = 35 degrees

angle FLJ = 55 degrees

=================================================

Explanation:

This problem is fairly tricky if you're not sure what to look for. A slight clue is that they've marked a red point that strangely doesn't have a label on it. It's a fairly small point but it's definitely there if you look closely. While this point's location isn't exactly what we want, we're fairly close. Start at point L and draw a ray through the center point P. Ray LP will intersect the circle at point A, as shown in the diagram below.

From here, draw segments FA and MA. Now notice that inscribed angle LMF = 55 and inscribed angle FAL both subtend the same arc. The term "subtend" basically means "cut off". This arc that the inscribed angles subtend is minor arc FL. A minor arc is where you travel the shorter path around the circle, which indicates its measure is less than 180 degrees.

Since inscribed angles LMF and FAL subtend the same minor arc, this makes the inscribed angles to be congruent.

In short: angle FAL is 55 degrees

----------------------

Segment LA goes through the center P. Through Thales theorem, we know that inscribed angle LFA is 90 degrees. Consequently, we can determine that inscribed angle FLA is 90-55 = 35 degrees.

Segment JL is tangent to the circle, meaning that angle ALJ is 90 degrees. So angle FLJ is 90-35 = 55 degrees.

It's not a coincidence that angle FLJ, angle FAL, and angle LMF are the same measure.

----------------------

We found that angle FAL was 55 degrees. Applying Thales theorem again shows that angle MAF is 90 degrees. Therefore, angle LAM is 90-55 = 35 degrees.

Focus now on triangle LMA. This is also a right triangle (Thales Theorem). The upper acute angle we found was angle LAM = 35, so the lower acute angle is ALM = 55.

Then we can find angle MLN = (angle ALN) - (angle ALM) = 90 - 55 = 35

In short, angle MLN = 35 degrees

Similar to the previous section, it is not a coincidence that angles LFM, LAM and MLN are the same measure.

------------------------

As an alternative, since we know angle FLJ = 55, and angle FLM is 90 degrees, this means...

(angle FLJ)+(angle FLM) + (angle MLN) = 180

55 + 90 + angle MLN = 180

145 + angle MLN = 180

angle MLN = 180 - 145

angle MLN = 35 degrees

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Answer: 1/2

Step-by-step explanation:

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- divide by 8 on both sides to get y=1/2x

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