Question

[25 POINTS] The approximate change in the value of f(x) = sqrt(2(x-1)) at x = 3 using differentials with dx = 0.01 is

Answer 1

Answer:

$\frac{1}{200}$

Step-by-step explanation:

Find the derivative of the function when x=3

$y=\sqrt{2(x-1)}$

$\frac{dy}{dx}=\frac{1}{\sqrt{2(x-1)}}$

$\frac{dy}{dx}=\frac{1}{\sqrt{2(3-1)}}$

$\frac{dy}{dx}=\frac{1}{\sqrt{2(2)}}$

$\frac{dy}{dx}=\frac{1}{\sqrt{4}}$

$\frac{dy}{dx}=\frac{1}{2}$

Since the change in the value of the function is $dy$ and we know that the change in x is $dx=0.01$, then we have:

$\frac{dy}{dx}=\frac{1}{2}$

$dy=\frac{1}{2}dx$

$dy=\frac{1}{2}(0.01)$

$dy=\frac{1}{200}$

Therefore, the 2nd option is correct