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evablogger [386]
3 years ago
12

Given that G(x) = 5/2x - 7/2 what is x if G(x) = 39

Mathematics
2 answers:
Evgen [1.6K]3 years ago
4 0

If G(x) = 39, then

5/2x - 7/2 = 39

Multiplying both sides by 2, we get

5x - 7 = 78

5x = 78 + 7

5x = 85

x = 17

I hope this answer helps!

Solnce55 [7]3 years ago
4 0

Answer:

x=17

Step-by-step explanation:

Given that G(x)=5/2x-7/2

Given that G(x)=39

Which is 39=5/2x-7/2

Multiply through by 2

39×2=(5/2x)2 - (7/2)2

78=5x -7

5x=78+7=85.

x=85/5

x=17.

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Answer:

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(536.46, 603.54)

Step-by-step explanation:

<u><em>Step:-1</em></u>

Given that the mean of the Population = 540HP

Given that the size of the sample  'n' = 9

Given that the mean of the sample = 570HP

Given that the sample standard deviation = 30HP

<u><em>Step(ii):-</em></u>

<u><em>Degrees of freedom = n-1 =9-1 =8</em></u>

<u><em>t₀.₀₀₅ = 3.3554</em></u>

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(x^{-} - t_{\frac{0.01}{2} ,8} \frac{S.D}{\sqrt{n} } ,x^{2}  + t_{\frac{0.01}{2},8 } \frac{S.D}{\sqrt{n} } )

(570-3.354\frac{30}{\sqrt{9} } , 570+3.354\frac{30}{\sqrt{9} } )

(570 - 33.54 , 570+33.54)

(536.46 , 603.54)

<u><em>Final answer</em></u> :-

<em>The 99% of a confidence interval for the average maximum HP for the experimental engine.</em>

<em>(536.46, 603.54)</em>

<em></em>

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please mark as brainliest or give good rating if this helped you. I hope it did!
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